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bezimeni [28]
3 years ago
12

Gyaltsho's mass would be 32kg​

Mathematics
1 answer:
adoni [48]3 years ago
4 0

Answer:

What type of question is this?

Step-by-step explanation:

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Is there a answer to this
hodyreva [135]

Answer:

mean=71

Step-by-step explanation:

Mean x¯¯¯x¯

71

Median x˜x~

72

Mode

64, 83, 79, 38, 81, 90, 59, 93, 70, 73, 71, 51

Range

55

Minimum

38

Maximum

93

Count n

12

Sum

852

Quartiles

Quartiles:

Q1 --> 61.5

Q2 --> 72

Q3 --> 82

Interquartile

Range IQR

20.5

Outliers

none

5 0
3 years ago
Find the lateral area for the pyramid with the equilateral base
likoan [24]
<h3>The lateral area for the pyramid with the equilateral base is 144 square units</h3>

<em><u>Solution:</u></em>

The given pyramid has 3 lateral triangular side

The figure is attached below

Base of triangle = 12 unit

<em><u>Find the perpendicular</u></em>

By Pythagoras theorem

hypotenuse^2 = opposite^2 + adjacent^2

Therefore,

opposite^2 = 10^2 - 6^2\\\\opposite^2 = 100 - 36\\\\opposite^2 = 64\\\\opposite = 8

<em><u>Find the lateral surface area of 1 triangle</u></em>

\text{ Area of 1 lateral triangle } = \frac{1}{2} \times opposite \times base

\text{ Area of 1 lateral triangle } = \frac{1}{2} \times 8 \times 12\\\\\text{ Area of 1 lateral triangle } = 48

<em><u>Thus, lateral surface area of 3 triangle is:</u></em>

3 x 48 = 144

Thus lateral area for the pyramid with the equilateral base is 144 square units

5 0
3 years ago
An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con
natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

L = 3w --- (1)volume = l \times w \times h \\ \\ 88 =  (3w)   \times w  \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\

The construction cost now is:

C = 4(l \times w) + 2 ( w  \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w  \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}

Now, to determine the minimum cost:

\dfrac{dC}{dw}= 0  \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}

w = \dfrac{88}{3(3)}^{1/3} \ feet

Now;

length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet

height = ( 88})^{1/3} (3)^{1/3} \ feet

6 0
3 years ago
Charlotte divided a whole pizza into 4 pieces. one piece formed a straight angle. one formed a right angle. two pieces formed ac
Minchanka [31]
You have to draw a pie graph.

The first piece (with the straight angle) cuts the pie in half. 

The second piece cuts the remaining half in halves (making a quarter).

The third and fourth pieces are the same as each other. So they must each have an angle of 45 degrees. Each of these is an eighth of the total pie.

Should be fairly easy. Good luck!
7 0
3 years ago
Solve the system: 6x=25y+1 5x−16y=−4
jeka94

Answer:

The solution is (x,y)=(-4,-1)

Step-by-step explanation: Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.

5 0
3 years ago
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