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il63 [147K]
3 years ago
8

F(x)= 9x + 2 over 3X^2+5x-12

Mathematics
1 answer:
Maurinko [17]3 years ago
4 0
Here the only limitation on the domain exists when the denominator is equal to zero, as division by zero has no meaning and is not "allowed" because of its meaninglessness. :)

Factor the denominator to find the excluded values of x...

3x^2+5x-12

3x^2+9x-4x-12

3x(x+3)-4(x+3)

(3x-4)(x+3)

So x CANNOT equal 4/3 or -3 (all other real values of x are part of the domain) so the domain is:

x=(-oo, -3),(-3, 4/3),(4/3, +oo)
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