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il63 [147K]
3 years ago
8

F(x)= 9x + 2 over 3X^2+5x-12

Mathematics
1 answer:
Maurinko [17]3 years ago
4 0
Here the only limitation on the domain exists when the denominator is equal to zero, as division by zero has no meaning and is not "allowed" because of its meaninglessness. :)

Factor the denominator to find the excluded values of x...

3x^2+5x-12

3x^2+9x-4x-12

3x(x+3)-4(x+3)

(3x-4)(x+3)

So x CANNOT equal 4/3 or -3 (all other real values of x are part of the domain) so the domain is:

x=(-oo, -3),(-3, 4/3),(4/3, +oo)
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3 years ago
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8 0
3 years ago
-5x-4y=10
strojnjashka [21]

Answer:

y intercept = (0, ~-\frac{5}{2} )

x intercept = (-2, ~0)

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Step-by-step explanation:

-5x - 5y = 10

.

y intercept

\to x = 0

-5(0) - 4y = 10

-4y = 10

y = \frac{10}{-4}

y = -\frac{5}{2}

so, the answer is (0, ~-\frac{5}{2} )

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x intercept

\to y = 0

-5x - 4(0) = 10

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x = \frac{10}{-5}

x = -2

so, the answer is (-2, ~0)

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Happy to help :)

8 0
3 years ago
Read 2 more answers
Please help with this question.
rusak2 [61]
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6 0
4 years ago
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Answer:

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