The points you found are the vertices of the feasible region. I agree with the first three points you got. However, the last point should be (25/11, 35/11). This point is at the of the intersection of the two lines 8x-y = 15 and 3x+y = 10
So the four vertex points are:
(1,9)
(1,7)
(3,9)
(25/11, 35/11)
Plug each of those points, one at a time, into the objective function z = 7x+2y. The goal is to find the largest value of z
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Plug in (x,y) = (1,9)
z = 7x+2y
z = 7(1)+2(9)
z = 7+18
z = 25
We'll use this value later.
So let's call it A. Let A = 25
Plug in (x,y) = (1,7)
z = 7x+2y
z = 7(1)+2(7)
z = 7+14
z = 21
Call this value B = 21 so we can refer to it later
Plug in (x,y) = (3,9)
z = 7x+2y
z = 7(3)+2(9)
z = 21+18
z = 39
Let C = 39 so we can use it later
Finally, plug in (x,y) = (25/11, 35/11)
z = 7x+2y
z = 7(25/11)+2(35/11)
z = 175/11 + 70/11
z = 245/11
z = 22.2727 which is approximate
Let D = 22.2727
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In summary, we found
A = 25
B = 21
C = 39
D = 22.2727
The value C = 39 is the largest of the four results. This value corresponded to (x,y) = (3,9)
Therefore the max value of z is z = 39 and it happens when (x,y) = (3,9)
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Final Answer: 39
Answer:
look at this
Step-by-step explanation:
72ft
you do 8 times 2 is 16
34-16 is 18 then divide by 2 is 9
9 times 8 is 72
~JZ
Answer:
The amount invested in gold bullion by Mr. Eliot = $50,000
Step-by-step explanation:
Total amount of savings Me. Eliot ha s = $150,000
Let us assume the amount invested in gold bullion = $m
So, the amount invested in bank = $150,000 - m
Now, 5% on m = 
So, the profit in gold bullion = 0.05 m
and 3% on (150,000 -m) = 
= 4,500 - 0.03 m
So, the profit in bank = 4,500 - 0.03 m
Now, the total profit = $5,500
⇒Profit from gold bullion + ban = $5,500
⇒0.05 m + 4,500 - 0.03 m = $5,500
or, 0.02 m = 1000
⇒ m = 1000/0.02 = 50,000
Hence, the amount invested in gold bullion = m = $50,000
Answer
A: (1,7.5)
b:(0,6)
c: because the graph is linear graph and have a constant rate of change/ slope which is -1.5
Step-by-step explanation:
