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Fed [463]
3 years ago
7

The universal gas law, pV = nRT, describes the relationship among the pressure, volume, and temperature of a gas. p = pressure V

= volume T = temperature (Kelvin) n = number of moles (quantity of gas particles) R = universal gas constant At a constant temperature of 1 K, the pressure and volume of 1 mole of gas vary inversely. Use the values in the table to find the value of R. volume (Liters): 4.155, 16.62, 33.24. pressure: 2, 0.5, 0.25
Mathematics
2 answers:
kakasveta [241]3 years ago
5 0

Answer:

The value of R is, 8.31

Step-by-step explanation:

Given the universal gas law:

pV = nRT              ....[1]

where,

p = pressure

V = volume

T = temperature (Kelvin)

n = number of moles (quantity of gas particles)

R = universal gas constant

It is given that at a constant temperature of 1 K, the pressure and volume of 1 mole of gas vary inversely.

⇒T = 1 K and n = 1

Since, pressure and volume varies inversely.

⇒pV = k   where, k is constant

to find k:

From the given table:

p=2 and V = 4.155

then;

2 \cdot 4.155 = k

⇒8.31 = k

or

k = 8.31

pV =8.31

We have to find value of R:

Substitute pV = 8.31 and the given values in [1] we have;

8.31 = 1 \cdot R \cdot 1

⇒8.31 = R

or

R = 8.31

Therefore, the value of R is, 8.31

Step2247 [10]3 years ago
3 0

Answer:

R ≈ 8.31

Step-by-step explanation:

Filling in the given values ...

... pV = nRT

... 2·4.155 = 1·R·1

... 8.31 = R

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Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures (6x+20)^{\circ} and (x+100)^{\circ} are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16

Then

(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}

17. Two parallel lines are cut by transversal. Angles with measures (2x+12)^{\circ} and (3x-22)^{\circ} are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34

Then

(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}

18. Two parallel lines are cut by transversal. Angles with measures (6x-7)^{\circ} and (5x+10)^{\circ} are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17

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19. The diagram shows two complementary angles with measures 2x^{\circ} and 56^{\circ}. The measures of complementary angles add up to 90^{\circ}, then

2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17

Hence,

2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}

Check:

34^{\circ}+56^{\circ}=90^{\circ}

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m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}

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