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zysi [14]
3 years ago
11

Please help!!! 25 points!!

Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0
<h3>Answer: B) y = -x</h3>

==============================================

Work Shown:

g(x) = x^2-2

g(-2) = (-2)^2-2

g(-2) = 2

Saying (-2, g(-2)) is the same as saying (-2, 2)

---------------

g(x) = x^2-2

g(1) = 1^2 - 2

g(1) = -1

Saying (1, g(1)) is the same as saying (1, -1)

---------------

Let's find the slope of the line through (-2,2) and (1,-1)

m = (y2 - y1)/(x2 - x1)

m = (-1-2)/(1-(-2))

m = (-1-2)/(1+2)

m = -3/3

m = -1

Now turn to point slope form to find the equation

y - y1 = m(x - x1)

y - 2 = -1(x - (-2))

y - 2 = -(x + 2)

y - 2 = -x - 2

y-2+2 = -x-2+2 ... add 2 to both sides

y = -x

You could use the other point (1,-1) and you'd get the same answer. The slope m = -1 is the same each time.

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3 years ago
If a decimal number does not repeat, it ends with which number?
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A repetend / reptend

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HOPE IT HELPED

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Turn everything into fractions with common denominators:

\dfrac{3\sin^2x-2\cos^2x}{\cos^2x}=\dfrac{1-\cos^2x}{\sin^2x}

Recall that \cos^2x+\sin^2x=1, so we can simplify both sides a bit.

On the left:

\dfrac{3\sin^2x+3\cos^2x-5\cos^2x}{\cos^2x}=\dfrac{3-5\cos^2x}{\cos^2x}

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\dfrac{1-\cos^2x}{\sin^2x}=\dfrac{\sin^2x}{\sin^2x}=1

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So we have

\dfrac{3-5\cos^2x}{\cos^2x}=1\implies3-5\cos^2x=\cos^2x

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The following table gives the scores of 30 students in a mathematics examination. Scores 90–99 80–89 70–79 60–69 50–59 Students
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The given data is
Scores:      90-99  80-89  70-79  60-69  50-59
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Because we are to take the middle value for each group.
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Sx = 3*94.5 + 7*84.5 + 12*74.5 + 4*64.5 + 4*54.5 = 2245
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The mean is
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Calculate (Sx - m)² 
(Sx - m)² = 3*(94.5-74.833)² + 7*(84.5-74.833)² + 12*(64.5-74.833)²
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Answer:
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