1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergio039 [100]
3 years ago
7

When the smaller of two consecutive integers is added to two times the​ larger, the result is 35. Find the integers.

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

x+2(x+1)=35

x+2x+2=35

3x=35-2=33

x=33/3=11

smaller number=11

larger number=11+1=12

You might be interested in
Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang
Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population standard deviation is:

CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}

The information provided is:

<em>n</em> = 26

<em>s</em> = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652

\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}

     =\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3

Thus, the 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

3 0
3 years ago
Please help all i know is 10,000x 12/100=1,200+99=1,299
Liono4ka [1.6K]

Answer: Because 1 10,000 is the amount he earns a year so where does $99 come in?

Step-by-step explanation:

5 0
3 years ago
Sales of pizza increased from 500 to 705 in one year. what was the percent of increase? hurry​
qaws [65]

Answer:

41%

Step-by-step explanation:

Percent Increase = Amount of Increase / Original Amount

Percent Increase = (705 - 500) / 500

Percent Increase = 205/500 = 41/100 = .41 = 41%

...Making the correct response to this question 41%

3 0
3 years ago
A box of shredded wheat wheat weighs 0.35 .kg and a box of weetabix weighs 9/25 kg. Which box is heavier? Show your work.
MAXImum [283]

Answer:

weetablx is heavier

Step-by-step explanation:

lets simplify

wheat wheat - 0.35 kg

weetablx - 9/25

simplify into decimals

wheat wheat- 0.35 kg

weetablx- 0.36 kg

brainliest appreciated!

7 0
4 years ago
a man bought x boxes of doughnuts for $3.49 each. He paid with a $50 bill and received the correct amount of change. If he recei
Y_Kistochka [10]

Answer: F.  9 < x < 11

8 0
3 years ago
Other questions:
  • Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v, projvu u=(-8,8) , v= (
    12·1 answer
  • Answer this geometry question
    8·1 answer
  • Ronald spins a spinner that has 10 sections numbered from 1 to 10. What is the probability that the spinner lands on a prime num
    12·2 answers
  • identify a two-digit dividend that will result in a quotient with a remainder of 1 when the divisor is 4.
    11·1 answer
  • 104 2/3 written as a decimal?
    6·2 answers
  • What is the mean of 8,17,9,3,13
    9·2 answers
  • Pls help this was due three days ago
    7·1 answer
  • Select all equations that have one solution.
    12·1 answer
  • Helpppp i’ll give brainlest <br> find the approximate area of the shaded region
    6·2 answers
  • Solve for all real values of x.<br> x^2+6=0
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!