Answer:
Step-by-step explanation:
Lets find out first the Area of the rectangle building
A=50*100=5000 ft^2
we have 2 circles with the radius of 42 ft, r=21ft
Acircle=3.14*(21)^2=1384.74
Area of 2 circles=2*1384.74=2769.48
What is not covered by the rings is
5,000.00-2769.48=2230.52, rounded is 2231
Choice A
Answer:
g(-1) = -3
Step-by-step explanation:
g(-1) is the y value of the graph when x = -1
when x=-1 y=-3
g(-1) = -3
Answer:
![f(x) =\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%5Csqrt%5B3%5D%7Bx%7D)
Step-by-step explanation:
Hello!
Considering the parent function, as the most simple function that preserves the definition. Let's take the function given:
![g(x) = \sqrt[3]{x-5}+7](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx-5%7D%2B7)
To have the the parent function, we must find the parent one, let's call it by f(x).
![f(x) =\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%5Csqrt%5B3%5D%7Bx%7D)
This function satisfies the Domain of the given one, because the Domain is still
and the range as well.
Check below a graphical approach of those. The upper one is g(x) and the lower f(x), its parent one.
Answer:
z= 1.70 Since the test statistic is less than the critical value, we can conclude that the average length of an online video is not more than 8 minutes
Let
rA--------> radius of the circle R
rB-------> radius of the circle S
SA------> the area of the sector for circle R
SB------> the area of the sector for circle S
we have that
rA=3 ft
rB=6 ft
rA/rB=3/6----> 1/2----------->
rB/rA=2
SA=2π ft²
we know that
if Both circle A and circle B have a central angle , the square
of the ratio of the radius of circle A to the radius of circle B is equals to
the ratio of the area of the sector for circle A to the area of the sector for
circle B
(rA/rB) ^2=SA/SB-----> SB=SA*(rB/rA) ^2----> SB=(2) ^2*(2π)--->
SB----------- > 8π ft²
the answer is
the area of the sector for circle S is 8π ft²