Question

Solve for all real values of x. x^2+6=0

Answer 1

Answer:

-6+6=0

x^2=-6

sq root of -6 = x

Step-by-step explanation:

Answer 2

Hey there !

There are not atleast 1 real root of the given polynomial see the attachment for full explanation .

Also You can here see that here discriminant ( D ) = b² - 4ac = ( 0 )² - 4 × 1 × 6 = - 24 < 0 . So , By using definition of quadratic equation we can say that their is no real root of the given equation .