Solve for all real values of x. x^2+6=0
2 answers:
Hey there !
There are not atleast 1 real root of the given polynomial see the attachment for full explanation .
Also You can here see that here discriminant ( D ) = b² - 4ac = ( 0 )² - 4 × 1 × 6 = - 24 < 0 . So , By using definition of quadratic equation we can say that their is no real root of the given equation .
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The value of function on x=1 is 0.5
Step-by-step explanation:
In order to find the value of a function on given input, the input is put at the place of variable in the function.
Given function is:
We have to find the value of function on x = 1
Putting x = 1 in function
Hence,
The value of function on x=1 is 0.5
Keywords: Functions variables
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