Solve for all real values of x. x^2+6=0
2 answers:
Hey there !
There are not atleast 1 real root of the given polynomial see the attachment for full explanation .
Also You can here see that here discriminant ( D ) = b² - 4ac = ( 0 )² - 4 × 1 × 6 = - 24 < 0 . So , By using definition of quadratic equation we can say that their is no real root of the given equation .
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Hi there!
Since we have 2 variables in the given equation, and you only want to solve for one, the other will end up in your answer.
Step 1) Add 8y to both sides.
Step 2) Divide both sides by 6.
Final Answer -
Hope this helps! :D
Answer:
a. 473.15
b. C=K-273.15
C. 26.85
