Note that (a+b)^2 = a^2 + 2ab + b^2.
Therefore,
b^x (b^x )^2
<span>(2a^x +1/2 b^x)^2 becomes (2a^x)^2 + 2(2a^x)(-------- ) + ------------
2 4
LCD is 4. Thus, we have
4 [ (2a^(2x) ] + 8</span>a^x*b^x + b^(2x)
<span> </span>
Answer:
I think the second one
Step-by-step explanation:
I haven't learned how to do this.
V=hpir^2
d/2=r
d=8,
8/2=d/2=4=r
v=hpir^2
v=9pi4^2
v=9pi16
v=144pi
aprox
v=452.3
answer is C
To regroup is to use place value to exchange equal amount when renaming a number.