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lina2011 [118]
3 years ago
9

Which polynomial function could be represented by the graph below?

Mathematics
2 answers:
LuckyWell [14K]3 years ago
8 0

Answer:

f(x)=3x^2-18x+24

Step-by-step explanation:

we are given a graph

we can see that graph is of parabola

so, the function will be quadratic in nature

Firstly, we can identify zeros

zeros are x=2 and x=4

now, we can set up function

f(x)=a(x-2)(x-4)

now, we can select anyone point and find 'a'

at x=3 , y=-3

we can use it and find 'a'

-3=a(3-2)(3-4)

a=3

now, we can plug it back

and we get

f(x)=3(x-2)(x-4)

we can multiply it

and we get

f(x)=3x^2-18x+24

irakobra [83]3 years ago
5 0

Answer:

f(x) = 3x^2 – 18x + 24

Step-by-step explanation:

I put it into Desmos

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-3,6,-9,12,-15 which of the following represents the general term for the sequence give?
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The general term for the sequence a_{n}=(-1)^{n} 3 n

<h3><u>Solution:</u></h3>

Given sequence is -3, 6, -9, 12, -15

We have to find the general term of sequence

The terms in the sequence are found out by using the recursive definition:

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Let us use this definition to find out the terms and check if it matches our given sequence

\begin{array}{l}{\text { For } n=1:-(-1)^{n} 3 n=(-1)^{1} \times 3 \times 1=-3} \\\\ {\text { For } n=2:-(-1)^{n} 3 n=(-1)^{2} \times 3 \times 2=1 \times 6=6} \\\\ {\text { For } n=3:-(-1)^{n} 3 n=(-1)^{3} \times 3 \times 3=-1 \times 9=-9} \\\\ {\text { For } n=4:-(-1)^{n} 3 n=(-1)^{4} \times 3 \times 4=1 \times 12=12} \\\\ {\text { For } n=5:-(-1)^{n} 3 n=(-1)^{5} \times 3 \times 5=-1 \times 15=-15}\end{array}

Thus the general term is given by a_{n}=(-1)^{n} 3 n

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