Since DC = 12, then EF also = 12.
Both AD and BC are indicated to be the same .
So AE = (24 - 12) / 2 = 12/2 = 6
Now you have a right triangle with height DE = 8 and base AE = 6
Using the Pythagorean Theorem we can now find AD:
AD = √(8^2 + 6^2)
AD = √(64 + 36)
AD =√100
AD = 10
1/2 s + 3/4 s + 1/4 s + 4
((2+3+1)/4)s +4
6/4 s + 4
3/2 s + 4
8x^5\left(32\sqrt{2}x^2-\sqrt{2}x^4\right)
(?) is (-1) and that gray blank thing is 3.
Give a brainliest please:-)