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jarptica [38.1K]

3 years ago

10

NEED ANSWER ASAP!! PLEASE!!! The length of a rectangle is 1 foot more than twice the width. Write an expression that represents

the length.

1 answer:

Klio2033 [76]3 years ago

8 0

Answer:

The expressión that represents the length:

a = 2w + 1

a = length of the rectangle

w = width of the rectangle

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Anyone know how to do this?

Gekata [30.6K]

Answer: so i dont but hopefully someone cane help you

Step-by-step explanation:

4 0

2 years ago

Answer the following questions about the standard normal random variable Z. (Use 4 decimal places in your answers to parts a. th

Mashcka [7]

Answer:

a) 0.6636

b) 0.0951

c) 0,9474

d) 0.0047

e) 0.9957

f) 0.1308

Step-by-step explanation:

We look in tables z values and then we see carefully aereas inside normal curve

a) P[- 1.46 < z < 0.63 ] point 1.46 from table 0.0721 this s th area from value -1.46 to the left . And the value z = 0.63 corresond to the area 0.7357 which includes the area between 1.46 to the left tail, then we have to subtarct and get 0.6636 .

P[- 1.46 < z < 0.63 ] = 0.6636 66.36 %

b) P [ 0 < z < 1.31 ] we just need the area for point 1.31 that is 0.0951

P [ 0 < z < 1.31 ] = 0.0951 9.51 %

c) P [z > - 1.62 ] = 1 - 0.0526

P [z > - 1.62 ] = 0,9474 94.74 %

d) P[z < - 2.6 ] = 0.0047 0.47 %

e) P [ z < 2.63 ] = 1 - 0.0043

P [ z < 2.63 ] = 0.9957 99.57 %

f) P [ -2.58 < z < -1.1 ] = 0.1357 - 0.0049 =

P [ -2.58 < z < -1.1 ] = 0.1308 13.08 %

3 0

3 years ago

PLS HELP!!! WILL GIVE BRAINLIEST

GaryK [48]

Answer:

D) 4

Step-by-step explanation:

The point starts on 6 and goes down 2 times per point

since it is -2x

5 0

1 year ago

1 2/3 + 4 1/3 equals?

ahrayia [7]

Answer:

6

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Repost: Каков объем этой прямоугольной призмы?

torisob [31]

So first of all we should know that the <u>rectangular prism is a cuboid.</u>

$\\ \\$

<h3>Given :-</h3>

heigth = 9 in.
Length = 5 in.
Width = 4 in.

$\\$

<h3>To find:-</h3>

Volume of cuboid.

$\\$

<h3>Solution:-</h3>

We know:-

$\bigstar \boxed{ \rm volume \: of \: cuboid = length \times width \times height}$

$\\ \\$

So:-

$\dashrightarrow \sf volume \: of \: cuboid = length \times width \times height \\$

$\\ \\$

$\dashrightarrow \sf volume \: of \: cuboid = 9 \times 5 \times 4 \\$

$\\ \\$

$\dashrightarrow \sf volume \: of \: cuboid = 45 \times 4 \\$

$\\ \\$

$\dashrightarrow \bf volume \: of \: cuboid = 180 {in}^{3} \\$

Therefore option C is correct .

$\\ \\$

<h3>know more:-</h3>

$\\ \\$

$\begin{gathered}\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{CSA_{(cylinder)} = 2\pi \: rh}\\ \\ \bigstar \: \bf{Volume_{(cylinder)} = \pi {r}^{2} h}\\ \\ \bigstar \: \bf{TSA_{(cylinder)} = 2\pi \: r(r + h)}\\ \\ \bigstar \: \bf{CSA_{(cone)} = \pi \: r \: l}\\ \\ \bigstar \: \bf{TSA_{(cone)} = \pi \: r \: (l + r)}\\ \\ \bigstar \: \bf{Volume_{(sphere)} = \dfrac{4}{3}\pi {r}^{3} }\\ \\ \bigstar \: \bf{Volume_{(cube)} = {(side)}^{3} }\\ \\ \bigstar \: \bf{CSA_{(cube)} = 4 {(side)}^{2} }\\ \\ \bigstar \: \bf{TSA_{(cube)} = 6 {(side)}^{2} }\\ \\ \bigstar \: \bf{Volume_{(cuboid)} = lbh}\\ \\ \bigstar \: \bf{CSA_{(cuboid)} = 2(l + b)h}\\ \\ \bigstar \: \bf{TSA_{(cuboid)} = 2(lb +bh+hl )}\\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

6 0

2 years ago