Eighty percent of the students in a class (group A) share 40% of the candy equally. The remaining 20% of the students (group B)

Question

4 years ago

12

Eighty percent of the students in a class (group A) share 40% of the candy equally. The remaining 20% of the students (group B)

share the other 60% of the candy equally. The ratio of the amount of candy a student in group A has to the amount of candy a student in group B has is equal to what common fraction?

Mathematics

2 answers:

Ratling [72] · Answer 1 · 2022-01-16T12:33:26+03:00

Ratling [72]4 years ago

6 0

Answer:1/6

Step-by-step explanation:

mestny [16] · Answer 2 · 2022-01-16T10:43:49+03:00

Answer:

1/6

Step-by-step explanation:

There is x candy in total and y students in total.

Group A consists of 0.8y students, and group B consists of 0.2y students.

Group A gets 40% of x, or 0.4x. Each student in group A gets 0.4x/(0.8y) = 0.5x/y candy per person.

Group B gets 60% of x, or 0.6x. Each student in group B gets 0.6x/(0.2y) = 3x/y candy per person.

The ratio of candy each student in group A has to the amount of candy each student in group B has is:

(0.5x/y)/(3x/y) = 0.5/3 = 1/6