A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?
The positive whole-number factors of 30 are:
1, 2, 3, 5, 6, 10, 15 and 30.
So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that
P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors
=38=3×.125=.375
Answer:
Step-by-step explanation:
Answer:
-12
Step-by-step explanation:
(-4) - 8
Keep Flip Change
Keep
(-4)
Flip
- to +
Change to opposite
8 to -8
Result
-4 + -8 = -12
8(14-9)+5
________
2
3. + 6
8(5)+5
______
9 + 6
40 + 5
————
15
45
____
15
= 3
Answer:
18
Step-by-step explanation:
Given
x - 1 = 2 ( add 1 to both sides )
x = 3
Then
2x² = 2(3)² = 2 × 9 = 18
