<img src="https://tex.z-dn.net/?f=3%20%5Csqrt%7B2%7D%20%20-%204%20%20%5Cdiv%20%20%5Csqrt%7B3%7D%20%20-%202" id="TexFormula1" tit

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Marina86 [1]

2 years ago

le="3 \sqrt{2} - 4 \div \sqrt{3} - 2" alt="3 \sqrt{2} - 4 \div \sqrt{3} - 2" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

ivann1987 [24]2 years ago

4 0

Simplify the following:
(3 sqrt(2) - 4)/(sqrt(3) - 2)

Multiply numerator and denominator of (3 sqrt(2) - 4)/(sqrt(3) - 2) by -1:
-(3 sqrt(2) - 4)/(2 - sqrt(3))

-(3 sqrt(2) - 4) = 4 - 3 sqrt(2):
(4 - 3 sqrt(2))/(2 - sqrt(3))

Multiply numerator and denominator of (4 - 3 sqrt(2))/(2 - sqrt(3)) by sqrt(3) + 2:
((4 - 3 sqrt(2)) (sqrt(3) + 2))/((2 - sqrt(3)) (sqrt(3) + 2))

(2 - sqrt(3)) (sqrt(3) + 2) = 2×2 + 2 sqrt(3) - sqrt(3)×2 - sqrt(3) sqrt(3) = 4 + 2 sqrt(3) - 2 sqrt(3) - 3 = 1:
((4 - 3 sqrt(2)) (sqrt(3) + 2))/1

((4 - 3 sqrt(2)) (sqrt(3) + 2))/1 = (4 - 3 sqrt(2)) (sqrt(3) + 2):
Answer: (4 - 3 sqrt(2)) (sqrt(3) + 2)

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What is the lateral area of the cone? 10 yd and 12.1 yd

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Answer:

The lateral area will be "381 yd²". A further solution is provided below.

Step-by-step explanation:

The given values are:

Radius of cone,

r = 10 yd

Height of cone,

L = 12.1 yd

As we know,

The lateral surface area of cone is:

= $\pi r L$

On substituting the values, we get

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3 years ago

What two partial products would you add to find 513 x 46

Afina-wow [57]

First, let me do the Mathematical part of that, and then I shall explain the theory behind it.

Mathematical part:
We are going to multiply 513 with 46. So the two partial products that we are going to choose are 40 and 6.

Multiply 513 with 6 first.

  513
x46
--------------------------
  18 (as 6*3 = 18)
  60 (as 6*10 = 60; In 513, the digit at tenths place is 1, so 1*10=10)
  3000 (as 6*500 = 3000; In 513, 5 is at hundredth place, so 5*100=500)
  120 (as 40*3 = 120; since 4 is at the tenth place, so 4*10=40)
  400 (as 40*10 = 400)
20000 (as 40*500 = 20000)
--------------------------
23598 (Add all of them)

Theory:
As you can see above that we have chosen the two partial products individually which are 6 and 40. Since 4 in 46 is in tenth place, we have to consider it 40 (since 4*10 = 40). One by one, we first multiply 6 with 513. Then we move to the tenth place, and multiply 513 with 40. At the end, we have added all the results we found after multiplication.

Check: If we check the multiplication result by using the calculator, we would get the same result (23598).

Another Method (instant):
513 * (40+6) = (513*40) + (513*6) = 23598.

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