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3 years ago

Steps on how to find $2.99 socks; 5.5% markup

Mathematics

1 answer:

nikdorinn [45]3 years ago

6 0

Answer:

2.83

Step-by-step explanation:

so you would take 5.5% and turn it into a decimal .055

multiply .055 with 2.99

and you get 0.16445

take the starting price of 2.99 and subtract 0.16445 from it

you should get 2.82555 which would round up to 2.83

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CALCULUS: With what initial velocity much an object be thrown upward (from ground level) to reach the top of the Washington Monu

Zarrin [17]

S = Kt - 16t^2

setting s = 550 
550 = Kt - 16t^2 

this will reach the highest point when v = 0 
t = K/32 
when t = K/32 
550 = K^2/32 - K^2/64 
K^2 = 550*64 
K = 187.62 ft/s

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3 years ago

Michael buys some items at a grocery store.

tia_tia [17]

Answer:

Step-by-step explanation:

It's b my correct answer is b

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2 years ago

The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand

Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean strength of 50 items = 74.28

$\sigma$ = population standard deviation = 2.15

n = sample of items = 50

$\mu$ = population mean tensile strength after machine was adjusted

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $74.28-1.96 \times {\frac{2.15}{\sqrt{50} } }$ , $74.28+1.96 \times {\frac{2.15}{\sqrt{50} } }$ ]

= [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.

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3 years ago

1.In what ways did Egypt prosper during the reign of Hatshepsut? do your thing brainly!

Bond [772]

Answer:

She served as a queen, for Thutmose ll.

She served as queen alongside her husband, Thutmose II, but after his death, she claimed the role of pharaoh!. She reigned peace, she built temples and monuments, resulting in the flourishing of Egypt!

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2 years ago

Choose the best answer.

tekilochka [14]

I believe its D, 7.5% But check it with other sources because IM not 100% positive!

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2 years ago

Read 2 more answers

Steps on how to find $2.99 socks; 5.5% markup​

Steps on how to find $2.99 socks; 5.5% markup