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Alja [10]
3 years ago
7

Can someone teach me how to solve this please

Mathematics
1 answer:
Alexeev081 [22]3 years ago
7 0
Multiply it all together
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Bad gums may mean a bad heart. Researchers discovered that 82% of people who have suffered a heart attack had periodontal diseas
saveliy_v [14]

Answer:

37.27% probability that he or she will have a heart attack.

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Periodontal disease

Event B: Heart attack

Researchers discovered that 82% of people who have suffered a heart attack had periodontal disease, an inflammation of the gums.

This means that P(A|B) = 0.82

Only 33% of healthy people have this disease.

This means that P(A) = 0.33

Suppose that in a certain community heart attacks are quite rare, occurring with only 15% probability.

This means that P(B) = 0.15

If someone has periodontal disease, what is the probability that he or she will have a heart attack

P(B|A) = \frac{0.15*0.82}{0.33} = 0.3727

37.27% probability that he or she will have a heart attack.

6 0
3 years ago
You're having dinner at a restaurant that serves 555 kinds of pasta (spaghetti, bow ties, fettuccine, ravioli, and macaroni) in
NARA [144]

Answer:

19/20

Step-by-step explanation:

I got help on khan acadamy!!!!!

7 0
3 years ago
Which expression represents the sum of (2x-5y) and (x+y)?
trasher [3.6K]
(2x-5y) + (x+y)  
= (2x+x) + (-5y+y)
 = 3x + (-4y)
 = 3x-4y 
 So option A is the correct one.
4 0
3 years ago
If ( f ∘ g)(x) = x2 - 6x + 8 and g(x) = x - 3, what is f(x)?
DochEvi [55]
\bf \begin{cases}
(f\circ g)(x)=x^2-6x+8\\\\
(f\circ g)(x)=f(~~g(x)~~)\\\\
g(x)=x-3\\
\end{cases}
\\\\\\
\textit{now, one probability is }x^2-1
\\\\\\
f(x)=x^2-1\implies f(~~g(x)~~)=(x-3)^2-1
\\\\\\
f(~~g(x)~~)=(x^2-6x+9)-1\implies f(~~g(x)~~)=x^2-6x+8
5 0
3 years ago
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
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