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3 years ago

Rearrange to make x the subject 4(x – 3) = y a

Mathematics

2 answers:

Svet_ta [14]3 years ago

6 0

Answer:

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amm18123 years ago

5 0

Answer: If i mis understood the question just comment and ill redo it.

Step-by-step explanation: Please give brainliest.

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Two angles in a triangle measure (2.3x+25)° and (5.8x+11)°. what is the value of x if the two angles are congruent to one anothe

Anton [14]

Answer:

The answer is D. x= 4

Step-by-step explanation:

The angles are congruent so

2.3x +25 = 5.8x + 11

2.3x - 5.8x = 11 - 25

-3.5x = -14

x = 14/3.5

x = 4.

5 0

3 years ago

Read 2 more answers

A rectangle has an area of 99 square in. What is the length of the long side?

OLga [1]

Answer:

The longer length is either 99, 33 or 11 inches

Step-by-step explanation:

Given

$Area = 99$

Required

The length of the longer side

Area of a rectangle is:

$Area = Length * Width$

List out all possible products that give 99 [Assume the dimension are whole numbers]

$Length * Width = 99 * 1 = 99$

$Length * Width = 33 * 3 = 99$

$Length * Width = 11 * 9 = 99$

List out the longer factors

$L = \{99, 33, 11\}$

<em>Hence, the longer length is either 99, 33 or 11 inches</em>

8 0

3 years ago

What is 0÷0 plz find out

Andru [333]

Answer:

0 divided by 0 is impossible because you can't divide something by 0.

Step-by-step explanation:

Thanks for the free points :D

5 0

2 years ago

Read 2 more answers

Which one is bigger 0.000029 or 0.000014? And why!

inessss [21]

0.000029. Because the number 14 is less than 29.

6 0

3 years ago

Use the method of undetermined coefficients to solve the given nonhomogeneous system. x' = −1 5 −1 1 x + sin(t) −2 cos(t)

AlekseyPX

It looks like the system is

$x' = \begin{bmatrix} -1 & 5 \\ -1 & 1 \end{bmatrix} x + \begin{bmatrix} \sin(t) \\ -2 \cos(t) \end{bmatrix}$

Compute the eigenvalues of the coefficient matrix.

$\begin{vmatrix} -1 - \lambda & 5 \\ -1 & 1 - \lambda \end{vmatrix} = \lambda^2 + 4 = 0 \implies \lambda = \pm2i$

For $\lambda = 2i$ , the corresponding eigenvector is $\eta=\begin{bmatrix}\eta_1&\eta_2\end{bmatrix}^\top$ such that

$\begin{bmatrix} -1 - 2i & 5 \\ -1 & 1 - 2i \end{bmatrix} \begin{bmatrix} \eta_1 \\ \eta_2 \end{bmatrix} = \begin{bmatrix} 0 \\ 0 \end{bmatrix}$

Notice that the first row is 1 + 2i times the second row, so

$(1+2i) \eta_1 - 5\eta_2 = 0$

Let $\eta_1 = 1-2i$ ; then $\eta_2=1$ , so that

$\begin{bmatrix} -1 & 5 \\ -1 & 1 \end{bmatrix} \begin{bmatrix} 1 - 2i \\ 1 \end{bmatrix} = 2i \begin{bmatrix} 1 - 2i \\ 1 \end{bmatrix}$

The eigenvector corresponding to $\lambda=-2i$ is the complex conjugate of $\eta$ .

So, the characteristic solution to the homogeneous system is

$x = C_1 e^{2it} \begin{bmatrix} 1 - 2i \\ 1 \end{bmatrix} + C_2 e^{-2it} \begin{bmatrix} 1 + 2i \\ 1 \end{bmatrix}$

The characteristic solution contains $\cos(2t)$ and $\sin(2t)$ , both of which are linearly independent to $\cos(t)$ and $\sin(t)$ . So for the nonhomogeneous part, we consider the ansatz particular solution

$x = \cos(t) \begin{bmatrix} a \\ b \end{bmatrix} + \sin(t) \begin{bmatrix} c \\ d \end{bmatrix}$

Differentiating this and substituting into the ODE system gives

$-\sin(t) \begin{bmatrix} a \\ b \end{bmatrix} + \cos(t) \begin{bmatrix} c \\ d \end{bmatrix} = \begin{bmatrix} -1 & 5 \\ -1 & 1 \end{bmatrix} \left(\cos(t) \begin{bmatrix} a \\ b \end{bmatrix} + \sin(t) \begin{bmatrix} c \\ d \end{bmatrix}\right) + \begin{bmatrix} \sin(t) \\ -2 \cos(t) \end{bmatrix}$

$\implies \begin{cases}a - 5c + d = 1 \\ b - c + d = 0 \\ 5a - b + c = 0 \\ a - b + d = -2 \end{cases} \implies a=\dfrac{11}{41}, b=\dfrac{38}{41}, c=-\dfrac{17}{41}, d=-\dfrac{55}{41}$

Then the general solution to the system is

$x = C_1 e^{2it} \begin{bmatrix} 1 - 2i \\ 1 \end{bmatrix} + C_2 e^{-2it} \begin{bmatrix} 1 + 2i \\ 1 \end{bmatrix} + \dfrac1{41} \cos(t) \begin{bmatrix} 11 \\ 38 \end{bmatrix} - \dfrac1{41} \sin(t) \begin{bmatrix} 17 \\ 55 \end{bmatrix}$

7 0

1 year ago