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SCORPION-xisa [38]
4 years ago
14

Intersecting lines are ________ coplanar. never sometimes always

Mathematics
2 answers:
krok68 [10]4 years ago
8 0
Always
In order for them to intersect they ave to be in the same plane.
uysha [10]4 years ago
3 0

Answer:

ALWAYS ALWAYS ALWAYS

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19 POINTS AND ILL GIVE BRAINLIEST!!
Archy [21]

Answer:

3.104 (option c)

Step-by-step explanation:

3 + 0.1 + 0.004 = 3.104

6 0
3 years ago
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Plz do number 4. 5th grade math​
77julia77 [94]

Answer:

your answer would be 78

Step-by-step explanation:

     78

9/702

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4 0
3 years ago
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What is the value of X
Serga [27]

Answer:

X = 10.4

Step-by-step explanation:

Since the angle is a 90 degress angle we can assume that

39 + (5x-1) = 90 degrees.

Therefore we can subtract 39 from both sides which will give us

5x-1=51

Add 1 to both sides

5x = 52

Divide both sides by 5

x=52/5

The answer is

X = 10.4

Hope this helps! :)

7 0
2 years ago
Which expression is equivalent to -28x + 36 <br> A) -4(7x - 9) or B) 7(-4x +6)
Aleonysh [2.5K]

Answer:

Answer would be A. -4(7x-9)

4 0
3 years ago
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Suppose that a baseball is thrown upward with an initial velocity of 132 feet per second ​(90 miles per​ hour) and it is release
postnew [5]

Answer: it will take 8.25 seconds to reach maximum height

Step-by-step explanation:

Initial velocity, u of baseball = 132 feet per second. The height of the baseball, h in feet after t seconds is given by the function h = −16t^2 + 132t + 4

The given function is a quadratic equation. If values of height attained is plotted against time, the graph will take the shape of a parabola whose vertex corresponds to the maximum height attained by the baseball

Vertex of the parabola = -b/2a

a = - 16

b = 132

Vertex = - 132/-16× 2 = -132/32

Vertex = 4.125

The maximum height is 4.125 feets

To determine the time it will take to reach the maximum height of 4.125 feets, we will substitute h = 4.125 in the equation

4.125 = −16t^2 + 132t + 4

−16t^2 + 132t - 0.125 = 0

Applying the general formula for quadratic equations,

t = [- b ± √b^2 - (4ac)]/2a

a = -16

b = 132

c = -0.125

t = [- 132 ± √132^2 - 4(-16 × - 0.125)]/2× -16

t = [- 132 ± √17424 - 8)]/-32

t = [- 132 ± √17416]/-32

t = (-132 ± 132)/-32

t = (-132 + 132)/-32 or (-132 -132)/-32

t = 0 or -264/-32

t = 8.25 seconds

4 0
3 years ago
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