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Llana [10]
3 years ago
13

What is the constant of proportionality

Mathematics
1 answer:
Arada [10]3 years ago
4 0
I believe it's simply asking for the weight of a single egg
*assuming all egg weights are equal*
we simply divide our total weight by the number of eggs
264 \div 6 = 44
constant of proportionality is 44g per egg
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What value of z will make △DEF ≅ △JKI
Leto [7]

Answer:

z = 11

Explanation:

5y + 13 = 6y

Subtract 5y by both sides.

13 = y

Next,

z + 22 = 3z

Subtract z by both sides.

22 = 2z

Then, divide both sides by 2.

11 = z

Finally plug those answers into the equations.

5(13) + 13 = 78

6(13) = 78

(11) + 22 = 33

3(11) = 33

So △DEF ≅ △JKI because the value of z = 11.

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3 years ago
Y’all. I need you to help me
Sergio039 [100]

Answer:

10

Step-by-step explanation:

PQ/QR = ST/TR

17.5/QR = 7/4

QR = (17.5 x 4)/7

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QR = 10

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4 years ago
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Answer:

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Step-by-step explanation:

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The value of x is ____ °,and the value of y is____ °. this is really confusing help please..​
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Step-by-step explanation:

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Will give brainiest In △ABC, angle bisectors
EleoNora [17]

Answer:

m\angle CAB=102\dfrac{6}{7}^{\circ}\\ \\m\angle ABC=51\dfrac{3}{7}^{\circ}\\ \\m\angle ACB=25\dfrac{5}{7}^{\circ}

Step-by-step explanation:

AK is angle A bisector, then

m\angle BAK=m\angle KAC=x^{\circ}

BL is angle B bisector, then

m\angle ABL=m\angle CBL=y^{\circ}

Consider triangle ABL. The sum of the measures of all interior angles in this triangle is 180^{\circ}, then

m\angle BAL+m\angle ALB+m\angle LBA=180^{\circ}\\ \\2x+2y+y=180\\ \\2x+3y=180

Consider triangle ABK. In this triangle,

m\angle AKB=180^{\circ}-2x^{\circ} \ [\text{Supplementary angles}]

The sum of the measures of all interior angles in this triangle is 180^{\circ}, then

m\angle BAK+m\angle AKB+m\angle KBA=180^{\circ}\\ \\x+(180-2x)+2y=180\\ \\2y-x=0

Hence,

x=2y\\ \\2(2y)+3y=180\\ \\4y+3y=180\\ \\7y=180\\ \\y=\dfrac{180}{7}=25\dfrac{5}{7}\\ \\x=\dfrac{360}{7}=51\dfrac{3}{7}

Find the measures of the triangle ABC:

m\angle CAB=2x^{\circ}=102\dfrac{6}{7}^{\circ}\\ \\m\angle ABC=2y^{\circ}=51\dfrac{3}{7}^{\circ}\\ \\m\angle ACB=180^{\circ}-102\dfrac{6}{7}^{\circ}-51\dfrac{3}{7}^{\circ}=25\dfrac{5}{7}^{\circ}

8 0
4 years ago
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