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adell [148]
3 years ago
10

15 = p - 12 btw i got points a lot

Mathematics
2 answers:
Marizza181 [45]3 years ago
6 0
The answer would be 27 because 15+12=27 so 27-12=15
myrzilka [38]3 years ago
5 0

Please, when posting a problem, include the instructions. My educated guess is that the instructions here are "Solve the following equation for p."


15 = p - 12


Isolate (solve for) p by adding 12 to both sides of this equation:


15 + 12 = p. Therefore, p = 27

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Please help me I dont understand any of this. Ps it might take me a while for me to understand. :/
Tems11 [23]

How to clear an equation/solve for any given variable?

Lets say you have two identical cups of coffee, a and b.

You can say they're both equal. If you want to add a tablespoon of sugar to cup a, and you also want both cups to remain equal, you'll have to add the same tablespoon of sugar to cup b.

We use this fact, called conservation of an equality, to clear an equation (A.K.A solving for a variable)

Mathematically speaking,

<em>Cups </em>a <em>and </em>b<em> are equal</em>

a=b

<em>If you modify </em>a<em>, you'll have to modify </em>b <em>the same way</em>

\begin{gathered} a+3=b+3 \\ a-1=b-1 \\ a\times4=b\times4 \\ \frac{a}{5}=\frac{b}{5} \end{gathered}

Now, let's apply that logic to the equation we have.

We know cup of coffee a is

6y-1.5x

And cup b is

8

We also know both cups of coffee are equal, so

6y-1.5x=8

We're being asked to solve for y. In other words, we have to clear y from this expression.

Let's add our first tablespoon of sugar: adding 1.5x to both sides:

\begin{gathered} 6y-1.5x=8\rightarrow6y-1.5x+1.5x=8+1.5x \\ \rightarrow6y=8+1.5x \end{gathered}

See how the -1.5x canceled out? That's what we're looking for! We want y to be left alone in its side.

Now, let's divide both sides by 6 to cancel out the 6 from 6y:

\begin{gathered} 6y=8+1.5x\rightarrow\frac{6y}{6}=\frac{8+1.5x}{6} \\ \rightarrow y=\frac{8+1.5x}{6} \\ \rightarrow y=\frac{8}{6}+\frac{1.5}{6}x \\ \rightarrow y=1.33+0.25x \end{gathered}

He have cleared y / solved the equation for y

<em>Let's try with another example</em>

<em />

e.g:

<em>Solve the following equation for </em>b

3b+9a+12=6

Solution: Let's substract 12 from both sides:

\begin{gathered} 3b+9a+12=6\rightarrow3b+9a+12-12=6-12 \\ \rightarrow3b+9a=-6 \end{gathered}

Then, let's substract 9a from both sides

\begin{gathered} 3b+9a=-6\rightarrow3b+9a-9a=-6-9a \\ \rightarrow3b=-6-9a \end{gathered}

Let's divide both sides by 3

\begin{gathered} 3b=-6-9a\rightarrow\frac{3b}{3}=-\frac{6}{3}-\frac{9a}{3} \\ \rightarrow b=-2-3a \end{gathered}

8 0
1 year ago
How do I write- -3x+9y=-27 in slope intercept form?
Mumz [18]
The slope intercept form is like : y = mx +b that m is slope and b is y-intercept 
so you can say : 9y = 3x - 27 ⇒ 9/9y = 3/9x -27/9 ⇒ y = 1/3x -3 :))
i hope this be helpful 
have a nice day 
4 0
3 years ago
Read 2 more answers
If (x + y)^2 = 105 and x^2 + y^2 = 65, what is the value of xy?
lesya692 [45]
\boxed { \boxed {(a + b)^2 = a^2 + 2ab + b^2}}

(x + y) ^2 = 105

x^2 + 2xy + y^2 = 105

x^2 + y^2  + 2xy = 105


\text{Given that } x^2 + y^2 = 65,

65 + 2xy = 105

2xy = 105 - 65

2xy = 40

xy = 20

\boxed { \boxed {\text{Answer: xy = 20}}}
8 0
3 years ago
Which function in Excel is used to perform a test of independence? a. T.TEST b. CHISQ.TEST c. NORM.S.DIST d. Z.TEST
denis23 [38]

Answer:

b. CHISQ.TEST

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

The statistic is given by:

\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}

In order to calculate the p value we need to have in count the degrees of freedom , on this case df=(rows-1)(#cols-1). And we can calculate the p value would be given by:

p_v =P(\chi^2 >\chi^2_{calc})

But the correct comand is given by:

b. CHISQ.TEST(Actual range, Expected range)

We just need to put in one column the Observed values and in other the expectec values.

3 0
3 years ago
Pls HELP ive been trying to figure this out forever!!!
SOVA2 [1]

Answer:

I think is B .3 < x

hope it helps!

4 0
2 years ago
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