1. Step 2 : 6x - 8 = 12 + 2x
2. 2m = 8
3. Two
Standardised z score = (16.075 - 16) / 0.2 = 0.375
which gives a probability of 0.1462 for selecting a package of weight 16.075
the probability of weight being excess of 16.075 = 0.5 - 0.1462 = 03538
Probability of picking 16 in excess of 16-075 = 0.3538^16 = 6.0273 * 10^-8
The images to solve this problem is in the attachment.
Answer:
= 671.0 N;
= 300 N
Step-by-step explanation: From the image in the attachment and knowing that the box is in equilibrium, i.e., the "sum" of all the forces is 0, it is possible to conclude that:
=
and
= 
Using trigonometry, shown in the second attachment, the values for each force are:
sin 20° = 
=
. sin(20)
= 735.0.913
= 671.0
cos 20° = 
=
. cos (20)
= 735.0.408
= 300
The force of static friction is 671N and normal force is 300N