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Anuta_ua [19.1K]
3 years ago
9

Pls HELP ive been trying to figure this out forever!!!

Mathematics
1 answer:
SOVA2 [1]3 years ago
4 0

Answer:

I think is B .3 < x

hope it helps!

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The work of a student to solve the equation 4(2x − 4) = 8 + 2x + 8 is shown below:
Contact [7]
Step 2...first error...when distributing through the parenthesis, u multiply, not add.

4(2x - 4) = 8 + 2x + 8 =
8x - 16 = 16 + 2x <== correction

5 0
3 years ago
The image of the point (6, -9) under a translation is (11,-4). Find the coordinates
yaroslaw [1]

Answer:

( - 6 , - 1 )

Step-by-step explanation:

Let's find the rule of that transformation:

1 +  = 4 ⇒  = 3

9 +  = 10 ⇒  = 1

Thus, the rule of given transformation is ( x + 3 , y + 1 )

So, the image of the point ( - 9 , - 2 ) is

( - 9 + 3 , - 2 + 1 ) = ( - 6 , - 1 )

3 0
2 years ago
Read 2 more answers
What does 2.8- 4.4n- 2n + 7 equal?
boyakko [2]

Answer:

2.8- 4.4n- 2n + 7 = -6.4n + 9.8

Step-by-step explanation:

combined like term:

-4.4n - 2n = -6.4n

2.8 + 7 = 9.8

so all you do is combined together and got -6.4n + 9.8

5 0
3 years ago
Read 2 more answers
A ship travels 62.5 km in 1st hour of sailing. Starting from 2nd hour, the distance travelled per hour is x% of that in the prec
Bas_tet [7]
Speed of the ship in the second hour =  (62.5 * x ) / 100  kph.

In third hour it is  [(62 * x) / 100 ] * x/100]

is 4th hour its is the above * x/100 again  so we can now form the equation

62.5x      x          x
------- *   ----  *  ----    =  32
100      100      100

62,5 x^3 = 32,000,000
x^3 =  512,000
x = 80 <-----  Answer  to (a)

(b)  Ship travels 62.5 in first hour then  this falls by a common ratio of 0.8 each hour so we have a geometric sequence 

Dist travelled in 6 hours  =  a1  1 - r^n
                                                --------  = 62.5* (1 - 0.8^6) / 1 -0.8 = 230.56

                                               1 - r

Answer is    230.56 km 




5 0
3 years ago
Which point satisfies the system of equations y = 3x − 2 and y = -2x + 3?
Sedbober [7]

Answer:

(1,1)

Step-by-step explanation:

The choices are not visible, however are unnecessary to solve this problem.

Given y = 3x - 2 and y = -2x + 3

[Set them equal to each other]

3x - 2 = -2x + 3

[Find x]

3x + 2x - 2 = 3

3x + 2x = 5

5x = 5

x = 1

[Plug x = 1 to both equations to check and find y]

y = 3x - 2

y = 3(1) - 2 = 3 - 2 = 1

y = -2x + 3

y = -2(1) + 3 = -2 + 3 = 1

Both are equal to y = 1 when x = 1

The point is then: (1,1)

3 0
3 years ago
Read 2 more answers
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