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Svetach [21]
3 years ago
6

Use the bar graph to find the experimental probability of the event.

Mathematics
1 answer:
uysha [10]3 years ago
6 0

Answer: where is the bar graph?

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Figure ABCD is transformed to obtain figure A′B′C′D′:
xz_007 [3.2K]

Answer:

<u>Part A</u>

  1. Reflect over the y-axis:  (x, y) → (-x, y)
    A (-4, 4) → (4, 4)
    B (-2, 2) → (2, 2)
    C (-2, -1) → (2, -1)
    D (-4, 1) → (4, 1)
  2. Shift 4 units down:  (x, y-4)
    (4, 4-4) → A' (4, 0)
    (2, 2-4) → B' (2, -2)
    (2, -1-4) → C' (2, -5)
    (4, 1-4) → D' (4, -3)

<u>Part B</u>

Two figures are <u>congruent</u> if they have the same shape and size.  (They are allowed to be rotated, reflected and translated, but not resized).

Therefore, ABCD and A'B'C'D' are congruent.  They are the same shape and size as they have only be reflected and translated.

3 0
2 years ago
Can I get help with this
Hunter-Best [27]

Answer:

The correct option is;

B) -6

Step-by-step explanation:

The given parameters are;

The line of symmetry of f(x) = The line of the reflection of g(x) over the y-axis

f(x) = 3·x² + b·x + c

From the given graph of g(x), we have;

The vertex point of g(x) = (-1, 8)

The line of symmetry is the line x = -1

The image of the reflection of (x, y) over the y-axis is (-x, y)

The image of the vertex of g(x) following a reflection across the y-axis is (1, 8)

Therefore;

The line of symmetry of the image of g(x) following a reflection over the x-axis is the line x = 1

The line (axis) of symmetry of a quadratic function is the line x = -b/(2·a), which is a line that always go through the vertex of the parabola

Where;

a = The coefficient of x²

b = The coefficient of 'x'

For f(x) = 3·x² + b·x + c, a = 3, and b = b

Given that f(x) and the image of g(x) have the same line of symmetry, we have;

The line of symmetry of f(x) is x = 1

Therefore, from the formula for the line of symmetry, we have;

x = -b/(2·a)

x = 1

By substitution, we have;

1 =  -b/(2·a)

∴ -2·a = b

Given that a = 3, we get;

-2 × 3 = -6 = b

b = -6

3 0
3 years ago
2(a³+b²+11)+1(3+a³+b+11)
Ann [662]

Answer:

2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

2(a^3+b^2+11)+1(3+a^3+b+11)

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14

Therefore, 2(a^3+b^2+11)+1(3+a^3+b+11) is equal to:

2a^3+2b^2+22+a^3+b+14

Now, combining like terms using the commutative property of addition, we get:

=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36

Therefore, the simplified form is 3a^3+2b^2+b+36

8 0
3 years ago
Gloria has a package of gummy worms. There are four flavors of gummy worms in the package- cherry, grape, lemon, and orange,
Oliga [24]

Answer:1

Step-by-step explanation:it is right

3 0
3 years ago
I need your help please​
Bess [88]

56m^2

see the steps from the pic

4 0
3 years ago
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