Answer:
<h2>
w = -8</h2>
Step-by-step explanation:
Given the equation solved by Ernesto expressed as
, the extraneous solution obtained by Ernesto is shown below;

Hence, the extraneous solution that Ernesto obtained is w = -8
Answer:
2/3 cup
Step-by-step explanation:
Well we see that they both have a common demonitator...6
Next we see the difference on the top of 5-1
After this we add 4 back mon top of the bottom(6)
It can be simplified from 4/6--> 2/3
The original expression is given by:

The correct way to rewrite the expression is given by:

For this, we use two properties:
Associative property:
The way of grouping the factors does not change the result of the multiplication:
Commutative property:
The order of the factors does not vary the product:
A. 5
1st 2nd 3rd 4th 5th Month
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