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guapka [62]
3 years ago
8

(Financial application: compound value) Suppose you save $100 each month into a savings account with the annual interest rate 5%

. Thus, the monthly interest rate is 0.05/12 = 0.00417. After the first month, the value in the account becomes 100 * (1 + 0.00417) = 100.417 After the second month, the value in the account becomes (100 + 100.417) * (1 + 0.00417) = 201.252 After the third month, the value in the account becomes (100 + 201.252) * (1 + 0.00417) = 302.507 and so on. Write a program that prompts the user to enter a monthly saving amount and displays the account value after the sixth month. (In Exercise 5.30, you will use a loop to simplify the code and display the account value for any month.)
Computers and Technology
1 answer:
allochka39001 [22]3 years ago
7 0

Answer:

Follow the code or function below...

Do not forget the saving amount, and initialise the balance with that amount. Inside the loop, work out and add the interest and then add the saving amount for the next month.

Explanation:

inicial = float(eval(input('Enter the montly saving amount: ')))

x = (1 + 0.00417)

month_one = inicial * x

month_two = (inicial + month_one) * x

month_three = (inicial + month_two) * x

month_four = (inicial + month_three) * x

month_five = (inicial + month_four) * x

month_six = (inicial + month_five) * x

print('The sixth month value is: '+str(month_six))

Don't forget the saving amount, and initialise the balance with that amount. Inside the loop, work out and add the interest and then add the saving amount for the next month.

balance = 801

for month in range(6):

   balance = balance * (1.00417)

print(balance)

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Assume that a gallon of paint covers about 350 square feet of wall space. Create an application with a main() method that prompt
Makovka662 [10]

Answer:

<em>C++</em>

#include <iostream>

#include <cmath>

using namespace std;

///////////////////////////////////////////////////////////////////////

int noOfGallons(int wallArea) {

   int gallon = 350;

   int gallon_price = 32.0;

   float total_price = 0.0;

   ///////////////////////////////////////////

   float noOfGallons = (float)wallArea/(float)gallon;

   printf("No of gallons needed %.2f", noOfGallons);

   cout<<endl;

   //////////////////////////////////////////

  total_price = noOfGallons*gallon_price;

   return round(total_price);

}

int wallArea(int length, int width, int height) {

   int wall_area = length*width;

   int total_price = noOfGallons(wall_area);

}

///////////////////////////////////////////////////////////////////////

int main() {

   int length, width, height;

   ///////////////////////////////////////////

   cout<<"Enter length: ";

   cin>>length;

   

   cout<<"Enter width: ";

   cin>>width;

   

   cout<<"Enter height: ";

   cin>>height;

   

   cout<<endl;

   ///////////////////////////////////////////

   int total_price = wallArea(length, width, height);

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5 0
3 years ago
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seraphim [82]

Answer:

Integer.parseInt( stringVariable );

Explanation:

This function is used to convert the string into integer in java .Following are the program that convert the string into integer in java .

public class Main

{

public static void main(String[] args)  // main method

{

 String num = "1056"; // string variable

int res = Integer.parseInt(num);  //convert into integer  

System.out.println(res); // display result

}

}

Output:1056

Therefore the correct answer is:Integer.parseInt( stringVariable );

6 0
4 years ago
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