Of the 1184 students who attend utopia middle school, 12.5% walk to school. How many students walk to school?

Need answer ASAP pls it’s important

Sliva [168]

Hey buddy I am here to help!

total outcomes r = 36

multiples of 3 = 3,6

total outcomes of multiple fo 3 = 12

12/36 = 1/3

1/3 is the answer

Hope it helps!

Plz mark me brainliest!

6 0

3 years ago

The sum of two numbers is no more than 28. Let x represent the first number, and let y represent the second number. Which

Sphinxa [80]

The answer is the first one

7 0

3 years ago

How many frogs in the population do not have spots on their back

Rudiy27

I would go with then answer 168
Because if 12 of 180 has spots then you would subtract 12 to get how many will not have spots ....thats how I got the answer

Hope I helped Pls mark me as brainliest

8 0

3 years ago

a bag contains 16 red coins , 8 blue coins , and 8 green coins. A player wins by pulling a red coin from the bag. Is this game f

scZoUnD [109]

Answer:

Step-by-step explanation:

there are a total of 16+8+8=32 coins in bag

16 out of 32 are red

player wins by pulling a red coin

assume it is a single pull, the winning probability = 16/32 = 1/2

so it is 50/50 chance n hence a fair game

4 0

3 years ago

Read 2 more answers

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.