53,380 was the average last year .
<u>Step-by-step explanation:</u>
Here we have , So far this year, the average monthly revenue at Lexington Times is 50,711. That is 5% less than the monthly average was last year. We need to find that What was the average last year . Let's find out:
Let the monthly average was last year be x , According to question the average monthly revenue at Lexington Times is 50,711 but , That is 5% less than the monthly average was last year . Following equation for above scenario is :
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , 53,380 was the average last year .