Answer:
So we use the t-distribution to compute a confidence interval for the average age of people using online dating services
Step-by-step explanation:
Confidence interval for a mean.
We have to decide between the t-distribution and the z-distribution.
T-distribution: We use the sample standard deviation.
Z-distribution: We use the population standard deviation.
In this problem:
The average age of those that were using online dating services was 35 years old with a sample standard deviation of 12 years.
So we use the t-distribution to compute a confidence interval for the average age of people using online dating services
Answer:

Step-by-step explanation:
We want to simplify:

We rewrite as positive index to get:

This simplifies to

This will finally give us:

We cannot simplify further.
Hence the simplest form is 
Answer:
18
Step-by-step explanation:
4.5 liters / .25 liters/pcup = 18 pcups
Answer:
0
Step-by-step explanation:
zero divided by anything that is integral is zero and 3 in a integer
0
Every even number is 2 away from the last.
0, 2, 4, 6, 8, 10, 12, 14...etc.
If we had an even number p, then the next three even numbers would be
p+2, p+4, and p+6.
<em>(If we had an odd number p, then the next three even numbers would be</em>
<em>p+1, p+3, and p+5. I'm not sure if p is even is implied in the question. Technically the answer would be p - p mod 2 + 2, where p is an interger...that gets into more technical function stuff, though.)</em>