Answer:

Step-by-step explanation:
<u>Theorem: The diagonals of a kite are perpendicular.</u>
Let O be the point of intersection of the diagonals,
Applying Pythagoras Theorem, in right triangle WOX

Applying Pythagoras Theorem, in right triangle WOZ

Answer: a)
20 shirts | 349 + 20(4.8)
40 shirts | 349 + 40(4.8)
60 shirts | 349 + 60(4.8)
b) Tn = 349 + n(4.8)
c) (1000 - 349)/4.8 rounded down.
Answer:
Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.
Step-by-step explanation:
By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.
Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.
By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.
Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625
y^2-y^2+0.5y+2.25–4.0625=0
0.5y- 1.8125=0
0.5y=1.8125
y=1.8125/0.5= 3.625
Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder
Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625
L^2=13.140625–0.90625+4.0615=15.390625
L= (15.390625)^1/2= 3.92 meters length of ladder
<em>hope it helps...</em>
<em>correct me if I'm wrong...</em>
Answer:
r = 4.908
Step-by-step explanation:
V = 885
height (given in the picture) = 11.7
V =
h
V = (3.14)(
)(h)
885 = (3.14)(
)(11.7)
885/3.14/11.7 = 
Take the square root and you get 4.908.
Answer: Maximum height = 105 feet
And, It takes 9/4 seconds to reach that point.
Step-by-step explanation:
Here the given function that shows the height of the pumpkin,
--------(1)
Where t is the time in second.
Differentiating equation (1) with respect to t,
We get, 
Again differentiating above equation with respect to t,
We get, 
For maximum or minimum, 



At t = 9/4 , h''(t) = Negative value,
Therefore, At t = 9/4 seconds, h(t) is maximum,
And, the maximum value is,



Therefore, the maximum height of the pumpkin is 105 feet at 9/4 seconds