To find the volume you use the formula—> length x width x height.
For the first problem you’ll solve 5 x 3 x 2 which is 30.
For the second one you’ll do the same thing. For this one you’ll do 3 x 3 x 2 which is 18.
Answer:
The graph has a removable discontinuity at x=-2.5 and asymptoe at x=2, and passes through (6,-3)
Step-by-step explanation:
A rational equation is a equation where

where both are polynomials and q(x) can't equal zero.
1. Discovering asymptotes. We need a asymptote at x=2 so we need a binomial factor of

in our denomiator.
So right now we have

2. Removable discontinues. This occurs when we have have the same binomial factor in both the numerator and denomiator.
We can model -2.5 as

So we have as of right now.

Now let see if this passes throught point (6,-3).


So this doesn't pass through -3 so we need another term in the numerator that will make 6,-3 apart of this graph.
If we have a variable r, in the numerator that will make this applicable, we would get

Plug in 6 for the x values.



So our rational equation will be

or

We can prove this by graphing
Answer:
Step-by-step explanation:
2x - 9y = 23
5x - 3y = -12x - 9y = 23
5x - 3y = -12x - 9y = 23
5x - 3y = -12x - 9y = 23
5x - 3y = -1
Answer:
11
Step-by-step explanation:
Area = LW
We know that the w = 2
We are told that the L (length) is three less than an unknown number so that mean L = (x - 3)
We are then told that the area = 22 square inches.
Area = LW
22 = (x - 3)2
Now solve for x
22 = (x - 3)2
Distribute the 2
22 = 2x - 6
22 + 6 = 2x
28 = 2x
28 / 2 = 2x / 2
14 = x
x = 14
Now take 14 and subtract 3
14 - 3 = 11
Unknown number = 11
Area = LW
L = 11
W = 2
Area = 22
11 * 2 = 22
Answer:
<h3><em>4 × 3 + 3²</em></h3><h3><em>4 × 3 + 9</em></h3><h3><em>12 +</em><em>9</em></h3>
<em>21</em>
<em>Therefore</em>
<em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em>
<em>h</em><em>o</em><em>p</em><em>e</em><em> </em><em>h</em><em>e</em><em>l</em><em>p</em><em>s</em><em>~</em>