Question↓
You are purchasing a new printer. Which of the following is the most important requirement?
Answer↓
A. Is the printer compatible with your computer's operating system?
If The Printer is Not Compatible With your Computer you will not Be able to Use Therefore, you Will have to buy a New One.
xXxAnimexXx
Hope this Helps! ^ω^
Answer:
7 page faults
Explanation:
I have created a small Java program that can be seen in the attached picture below. This Java program uses an LRU algorithm in order to find the number of page faults within an array of page references from the references given in the question. Using these references, and the java program we can see that there are a total of 7 page faults. This can be seen in the output highlighted by red in the picture below.
Answer:
- You need to create a variable outside (before) the input loop.
- You need a variable inside your loop that temporarily holds the user input.
- In your loop, you will compare if the variable outside the loop is greater than (or less than) the new user input.
I don't know what program language you are using, but I will use python since it's easy to read and you will get the idea if you're using a different programming language.
<u>Code (Python)</u>
largestnum = 0
for x in range(6): <em>#loops 6 times</em>
newnum = int(input("Enter a number: ")) #ask user for input & converts to int.
if newnum > largestnum: <em>#if new number is greater than largest num </em>
largestnum = newnum <em>#make it the largest number</em>
<em> </em>print("Largest:", largestnum)
The reason why you need a variable outside of the loop is because after the loop is done all variables inside the loop are trashed and can no longer be accessed outside of the loop.
First of all, we will need a function that checks if a number is prime or not:
boolean isPrime(int n){
for(int i=2; i<=math.sqrt(n); i++){
if(n % i == 0) return false;
}
return true;
}
Then, in the main program, we will call this function with all the desired inputs, and we will print the prime numbers:
for(int n=100; n<= 1000; n++){
if(isPrime(n)) print(n);
}
