All categories

3 years ago

For each pair of shapes, decide whether or not Shape A is congruent to Shape B. Explain your reasoning.

Mathematics

1 answer:

WINSTONCH [101]3 years ago

5 0

Shape A is congruent to Shape B because If you were to rotate one of the two and flip it the would like up and match.

You might be interested in

Emay ears $15 for each car she washes. Create an equation to represent the relationship between the number of cars

emmasim [6.3K]

Answer:

$25

Step-by-step explanation:

8 0

3 years ago

MAXImum [283]

Answer:

the overall verical change is down 296 feet

Step-by-step explanation:

-296+140= -156

-156-140=-296

3 0

3 years ago

PLEEEEASE HELP ME!!

mixer [17]

Answer:

umm km / nk

Step-by-step explanation:

I DONT know if this is right...…can u plz mark me brainiest? I really need it!!!!

7 0

3 years ago

Read 2 more answers

Please help me with this homework question

castortr0y [4]

Answer:

∠ADB≅∠ABC by the Alternate Interior Angles Theorem

∠CAD≅∠ACB by the Alternate Interior Angles Theorem

∠BAD and ∠ADV are supplementary by the Consecutive Interior Angle Theorem

∠ABC and ∠BCD are supplementary by the Consecutive Interior Angle Theorem

5 0

3 years ago

A veterinarian wants to know if pit bulls or golden retrievers have a higher incidence of tooth decay at the age of three. The v

BigorU [14]

Answer: B) [-0.0332,0.1332]

Step-by-step explanation: <u>Confidence</u> <u>Interval</u> is an interval where we can be a percentage sure the true mean is.

The confidence interval for a difference in population proportion is calculated following these steps:

First, let's find population proportion for each population:

$p_{1}=\frac{30}{120}=0.25$

$p_{2}=\frac{32}{160}=0.2$

Second, calculate standard deviation for each proportion:

$\sigma_{1}=\sqrt{\frac{0.25(0.75)}{120} } = 0.0395$

$\sigma_{2}=\sqrt{\frac{0.2(0.8)}{160} } = 0.0316$

Now, we calculate standard error for difference:

$SE=\sqrt{\sigma_{1}^{2}+\sigma_{2}^{2}}$

$SE=\sqrt{0.0395^{2}+0.0316^{2}}$

SE = 0.0505

The z-score for a 90% CI is 1.645.

Then, confidence interval is

$p_{1}-p_{2}$ ± z-score.SE

$0.25-0.2$ ± $1.645(0.0505)$

0.05 ± 0.0831

The limits of this interval are:

inferior: 0.05 - 0.0831 = $-0.0332$

superior: 0.05 + 0.0831 = 0.1332

The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is $[-0.0332,0.1332]$ .

8 0

3 years ago