<span>D. L.A. to Flagstaff, 465 miles; Flagstaff to Albuquerque, 345 miles
The answer above is correct.
810 - 120 = 690 ; 690 / 2 = 345 mi ( Flagstaff to Albuquerque )
810 - 345 = 465 mi ( L.A. to Flagstaff )
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Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have

When t = 0, A(0) = 0 (since the forest floor is initially clear)


So, D = R - A =

when t = 0(at initial time), the initial value of D =

Answer:
The correct answer to this question is that the cheetah can run 369,000 feet per hour. We can work this out in the following way:
One mile equals 1760 yards
In feet that is 3 x 1760 or 5,280
So Feet per hour will be 5280 x 70 or
369,600 feet per hour.
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Step-by-step explanation: