Important: If you're discussing squares, please express "the square of x" as x^2 (not as x2).
Please note that your y=x^2+3 is NOT a line. I will assume (probably incorrectly!) that you meant y=2x+3. The slope of this line is 2, so the slope of any line perpendicular to y=2x+3 is -1/2.
Now use the point-slope equation of a straight line:
y-8 = (-1/2)(x-1) (answer)
Answer:
5
Step-by-step explanation:
Answer:
Adjust the compasses' width to the point Q. The compasses' width is now equal to the length of the line segment PQ.
Step-by-step explanation:
Start with a line segment PQ that we will copy. Mark a point R that will be one endpoint of the new line segment. Set the compasses' point on the point P of the line segment to be copied. Adjust the compasses' width to the point Q. The compasses' width is now equal to the length of the line segment PQ.
The square root of 1444 is 38
(I used a calcultor)
