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Yakvenalex [24]

3 years ago

12

Can someone please help

1 answer:

QveST [7]3 years ago

8 0

B . 2 and 9... Brainleist please

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What does proportional mean?

skad [1K]

In mathematics, two variables are proportional if a change in one is always accompanied by a change in the other, and if the changes are always related by use of a constant multiplier. The constant is called the coefficient of proportionality or proportionality constant.

6 0

4 years ago

Read 2 more answers

Ac method for x^2+20x-8=0

yanalaym [24]

<h2>Explanation:</h2><h2></h2>

By using quadratic formula:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\quad a=1,\:b=20,\:c=-8$

$x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\cdot \:1\left(-8\right)}}{2\cdot \:1}$

$x=\frac{-20+\sqrt{20^2-4\cdot \:1\left(-8\right)}}{2\cdot \:1}:\quad 2\left(3\sqrt{3}-5\right)$

$x=\frac{-20-\sqrt{20^2-4\cdot \:1\left(-8\right)}}{2\cdot \:1}:\quad -2\left(5+3\sqrt{3}\right)$

So the solutions are:

$\boxed{x=2\left(3\sqrt{3}-5\right),\:x=-2\left(5+3\sqrt{3}\right)}$

5 0

3 years ago

What’s the answer and how do you figure these out?

Nostrana [21]

<2 = 35° because they form an S angle. S angles are alternating angles

4 0

3 years ago

Solve the equation by factoring. 5z^2-21z+4=0

bogdanovich [222]

Factorise to (5z-1)(z-4) = 0
then put 5z-1 = 0 so 5z = 1 z = 1/5
z-4=0 z = 4
z = 1/5 and 4

6 0

3 years ago

Read 2 more answers

Theequationforlineucanbewrittenasy = 6x + 6 . Line v , whichisperpendiculartoline u , includes the point (10, –5) . What is the

PolarNik [594]

Answer:

$y=\frac{-1}{6}x-\frac{10}{3}$

Step-by-step explanation:

Slope intercept form of the equation of a line is $y=mx+b$ where m denotes the slope of line and $b$ denotes the y-intercept.

Equation of a line u is $y=6x+6$

Here, slope of line u = m = 6

As the line v is perpendicular to line u, product of slopes of both the lines is equal to $-1$ .

Slope of line v $=\frac{-1}{6}$

So, slope intercept form of the line v is $y=\frac{-1}{6}x+b$

As point $(10,-5)$ lies on the line v, put $(x,y)=(10,-5)$ in equation $y=\frac{-1}{6}x+b$

$-5=\frac{-1}{6}(10)+b\\-5=\frac{-5}{3}+b\\ -5+\frac{5}{3}=b\\\frac{-15+5}{3}=b\\\\\frac{-10}{3}=b$

Equation of line v is $y=\frac{-1}{6}x-\frac{10}{3}$

3 0

3 years ago