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Karo-lina-s [1.5K]
3 years ago
5

What’s is the answer for this problem?

Mathematics
1 answer:
harina [27]3 years ago
8 0
U jut need to try ur best buddy
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Let the universal set, s, have 66 elements. a and b are subsets of s. set a contains 19 elements and set b contains 34 elements.
Otrada [13]

The cardinality of the union between two sets is given by

N(A\cup B) = N(A) + N(B) - N(A \cap B)

In fact, if an element is in both A and B, it is counted in both N(A) and N(B), so we're counting it twice. By subtracting the cardinality of the interserction, we're taking back one of these "extra-counted" element, and the count is correct. In your case, the numbers are

N(A \cup B) = 19+34-10 = 43

This means that the two sets cover, without repetitions, 43 of the 66 elements in the sets. So, there are

66-43 = 23

elements which are in neither A nor B

5 0
3 years ago
Help sleepyhelp asap
SVEN [57.7K]

Answer:

The one that has the number of meals in the side and the one that has number of days

Step-by-step explanation:

If it’s 3 meals a day u would want the one that says meals and days now if u look at the chart u can see that this one has 3 meals for one day which is the same as the equation she has

Hope this helps

8 0
3 years ago
A deck is in the shape of a right triangle. The area of the deck is 44 m². The length of one side of the deck next to the right
Andrews [41]
11m
The area of a triangle is bh/2. If we know the height (8m), we can plug it into a=bh/2 for a=8h/2 or a=4h or a/4=h
Since we know the area (44m^2), we can put that in for 44/4=h or h=11 metres.
8 0
3 years ago
List possible rational zeroes of the function. 3x^5-8x^4+6x^2+7x-12.
spayn [35]
First list all the positive and negative factors of the constant term in the expression: ±(1,2,3,4,6,12) these will be the values for "p"

Second list all the positive and negative factors of the leading coefficient:
±(1,3) these will be the values for "q"

Now list all the possible values of \frac{p}{q} these will be the possible rational zeros of the polynomial function:
±(\frac{1}{1} , \frac{1}{3} , \frac{2}{1} , \frac{2}{3} , \frac{3}{1} , \frac{3}{3}, \frac{4}{1}  , \frac{4}{3} , \frac{6}{1} , \frac{6}{3} , \frac{12}{1} , \frac{12}{3})

these can be reduced to the following list:
±(1,\frac{1}{3}, 2, \frac{2}{3}, 3, 4, \frac{4}{3}, 6, 12

This list represents the possible rational zeros of the function. You can then use synthetic division to narrow down the actual roots of the function.

8 0
3 years ago
Emily created a table to describe the weather conditions in her area on a specific day. What do the labels A and B in the table
Ksenya-84 [330]

Answer:

The answer is a is precipitation and air temperature

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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