Answer:
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
Step-by-step explanation:
Sample size, n = 51
p = 0.62
1 - p = 1 - 0.62 = 0.38
n = 515
Confidence level = 90% = Zcritical at 90% = 1.645
Confidence interval = (p ± margin of error)
Margin of Error = Zcritical * sqrt[(p(1-p))/n]
Margin of Error = 1.645 * sqrt[(0.62(0.38))/515]
Margin of Error = 1.645 * 0.0214
Margin of Error = 0.035203
Lower boundary = (0.62 - 0.035203) = 0.584797
Upper boundary = (0.62 + 0.035203) = 0.655203
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
10% off of 199.99 is 179.99
100% - 10% = 90% The 90% is how much you are going to pay.
90% into decimal form is 0.9
So you can do 199.99 x 0.9 = $179.99
Answer:4(3x+4y)
Step-by-step explanation: the gcf of 12x+16y is 4. we factor out 4 by dividing both terms by 4.
The first point is on the 10 minute line in between 4 and 6 kilometer line
The second point is on the 15 minute in between the 10 and 12 kilometers line
The third point is on the 20 minute line and 18 kilometer line
