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nikitadnepr [17]
3 years ago
13

Codio Challenge Activity PythonWe are passing in a list of numbers. You need to create 2 new lists in your chart, then put all o

dd numbers in one list put all even numbers in the other list output the odd list first, the even list secondTip: you should use the modulo operator to decide whether the number is odd or even. We provided a function for you to call that does this.Don’t forget to define the 2 new lists before you start adding elements to them.------------------------------------------------------------Requirements:Program Failed for Input: 1,2,3,4,5,6,7,8,9Expected Output: [1, 3, 5, 7, 9][2, 4, 6, 8]------------------------------------------------------------Given Code:# Get our input from the command lineimport sysnumbers = sys.argv[1].split(',')for i in range(0,len(numbers)):numbers[i]= int(numbers[i])def isEven(n) :return ((n % 2) == 0)# Your code goes here
Computers and Technology
1 answer:
lilavasa [31]3 years ago
7 0

Answer:

The python code is given below with lists defined.

Explanation:

import sys

def isEven(n) :

 return ((n % 2) == 0)  //for even items

numbers = sys.argv[1].split(',')

for i in range(0,len(numbers)):

 numbers[i]= int(numbers[i])

even = []

odd = []

for i in numbers:

   if isEven(i):

       even.append(i)  #adds i to even list if it is even

   else:

       odd.append(i)  #adds i to odd list if not even (odd)

print(odd)

print(even)

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Answer:

File manager

Explanation:

From the list of options 1 to 4, only option (2) is correct

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Having explained the options one after the other, <em>the file manager </em>is the answer to this question.

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(Count positive and negative numbers and compute the average of numbers) Write a program that reads an unspecified number of int
Papessa [141]

Answer:

Explanation:

Sorry it  is in Java, though you can covert it using converter

public class Exercise {

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 int positives = 0;  // Count the number of positive numbers

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 double total = 0;  // Accumulate a totol

 // Promopt the user to enter an integer or 0 to exit

 System.out.print("Enter an integer, the input ends if it is 0: ");

 int number = input.nextInt();

 if (number == 0) { // Test for sentinel value

  System.out.println("No numbers are entered except 0");

  System.exit(1);

 }

 while (number != 0) {// Test for sentinel value

  if (number > 0)

   positives++; // Increase positives

  else

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  number = input.nextInt();

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 // Calculate the average

 double average = total / count;

 // Display results

 System.out.println(

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Answer:

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Additionally, an information system or technology comprises of five (5) main components;

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Hence, information technology or system relies on the data it receives from its environment, processes this data into formats that are usable by the end users.

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