Question

What is the difference? X/x^2-16 minus 3/x-4

Answer 1

Answer:

$\frac{-2x-12}{x^2-16}$

Step-by-step explanation:

We want to find the difference;

$\frac{x}{x^2-16}-\frac{3}{x-4}$

The first denominator can be rewritten as;

$x^2-16=(x+4)(x-4)$

Therefore the least common denominator is $x^2-16$

We collect LCD to obtain;

$\frac{x-3(x+4)}{x^2-16}$

Expand the parenthesis to obtain;

$\frac{x-3x-12}{x^2-16}$

$\frac{-2x-12}{x^2-16}$

Answer 2

Answer:

b

Step-by-step explanation: