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3 years ago

The question is attached

Mathematics

1 answer:

noname [10]3 years ago

5 0

A and D you’re welcome

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30/root 3-3 root 5<br> Ple answer this question

adoni [48]

$\frac{30}{ \sqrt{3} - 3 \sqrt{5} } \\ \\ =\frac{30}{ \sqrt{3} - 3 \sqrt{5} } \times \frac{\sqrt{3} + 3 \sqrt{5}}{\sqrt{3} + 3 \sqrt{5}} \: \\ \\ that \: simply \: means \: multiplying \: by \: 1 \\ \\ \frac{30(\sqrt{3} + 3 \sqrt{5})}{ (\sqrt{3} + 3 \sqrt{5}) (\sqrt{3} - 3 \sqrt{5}) } \: \: \\ \\ by \: using \: formula \: {a}^{2} - {b}^{2} \\ \\ we \: get \\ \\ = \frac{30 \sqrt{3} + 90 \sqrt{5} }{ 3 - 45} \\ \\ = - \frac{30( \sqrt{3} + 3 \sqrt{5}) }{42} \\ \\ = - \frac{10( \sqrt{3} + 3 \sqrt{5}) }{14} \: \:$

4 0

3 years ago

Graphing Natural Exponential Functions In Exercise,sketch the graph of the function.See Example 1.

nata0808 [166]

Answer:

The graphic is attached

Step-by-step explanation:

x H(x)

0 6

≥5 lim┬(x→∞)⁡〖h(x)=5〗

≤5 lim┬(n→-∞)⁡〖h(x)= ∞〗

when x tends to infinity the function approaches five above (horizontal asymptote).

when x tends to infinity the function tends to infinity.

Success with your homework.

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6 0

3 years ago

1" represents 20 miles if the distance on the map between two towns on the river measures 2 5/8" how many miles apart are the to

Semenov [28]

Answer:

52.5 miles

Step-by-step explanation:

2 5/8" × 20 = 52.5

3 0

3 years ago

58, 72, 74, 92, 84, 40, 74, 81, 76, 83 What was the maximum score earned on Mr. Hill's final exam

alexandr402 [8]

Answer:

Step-by-step explanation:

Max= biggest number, surely?

4 0

3 years ago

Regard y as the independent variable and x as the dependent variable and use implicit differentiation to find dx/dy. x3y2 − x4y

Flauer [41]

$\bf x^3y^2-x^4y=4xy^3=0\\\\
-------------------------------\\\\
\left( 3x^2y^2+x^32y\frac{dy}{dx} \right)-\left( 4x^3y+x^4\frac{dy}{dx} \right)+4\left( 1\cdot y^3+x3y^2\frac{dy}{dx} \right)=0
\\\\\\
2x^3y\frac{dy}{dx}-x^4\frac{dy}{dx}+12xy^2\frac{dy}{dx}=4x^3y-3x^2y^2-4y^3
\\\\\\
\cfrac{dy}{dx}\left( 2x^3y-x^4+12xy^2 \right)=4x^3y-3x^2y^2-4y^3
\\\\\\
\cfrac{dy}{dx}=\cfrac{4x^3y-3x^2y^2-4y^3}{2x^3y-x^4+12xy^2}$

7 0

3 years ago

The question is attached​

The question is attached