Answer:
Step-by-step explanation:
given that a laptop company claims up to 11.0 hours of wireless web usage for its newest laptop battery life. However, reviews on this laptop shows many complaints about low battery life. A survey on battery life reported by customers shows that it follows a normal distribution with mean 10.5 hours and standard deviation 27 minutes.
convert into same units into hours.
X is N(10.5, 0.45)
a) the probability that the battery life is at least 11.0 hours
(b) the probability that the battery life is less than 10.0 hours
=
(c) the time of use that is exceeded with probability 0.97
=97th percentile
= 11.844
d) The time of use that is exceeded with probability 0.9 is
is 90th percentile = 10.885
Answer:
(A)
- P(60) = 78.98
- When the bookstore spends $60 on a textbook, the student pays $78.98
Step-by-step explanation:
Given:
P(x) = 1.053(x+0.25x)
P(60) = 1.053(60+0.25*60)
=1.053(60+15)
=1.053(75)
P(60)=$78.98
Since x is the cost from the publisher, when the bookstore spends $60 on a textbook, the student pays $78.98.
<u>The correct option is A.</u>
Answer:
24
Step-by-step explanation:
the question translates to asking how many times does 7/8 fit in 21, so 21 divided by 7/8.
when we divide by a fraction, we can multiply by it's inverse, so 21 divided by 7/8, is 21 multiplied by 8/7. so:
21×8/7 = (21×8)/7 = (21/7)×8 = 3×8 = 24
The mileage is 27.6 mi/gal
Miles driven = 552.4 mi
Calculate gallons used.
Answer: 20.015 gallons (approximately 20 gallons)