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3 years ago

Can you please say if the point will be on the line?

Mathematics

1 answer:

Tcecarenko [31]3 years ago

5 0

Answer:

The point will be on the line.

Step-by-step explanation:

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Megan earns $20.00 by walking dogs. She uses all of her earnings to buy a shirt for $12.85 and some stickers for $0.65 each. How

Leya [2.2K]

The answer is B: 11.

To solve it, you need to solve the equation: 20.00=12.85+0.65x

4 0

3 years ago

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language. Describe the

taurus [48]

Answer:

The distribution of sample proportion Americans who can order a meal in a foreign language is,

$\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})$

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

The sample size of Americans selected to disclose whether they can order a meal in a foreign language is, n = 200.

The sample selected is quite large.

The Central limit theorem can be applied to approximate the distribution of sample proportion.

The distribution of sample proportion is,

$\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})$

3 0

3 years ago

Included picture Question is not hard so please answer correctly

Alex777 [14]

It can sometimes be rational

7 0

2 years ago

Formulate the following problem as least squares problems. For each problem, give a matrixA and a vector b such that the problem

hammer [34]

Answer:

a) $A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]$

$b=\left[\begin{array}{ccc}0\\1\end{array}\right]$

b) $||Ax-b||^{2} =(-bx_{2}+4)^{2} (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}$

c) $A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]$

$x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]$

Step-by-step explanation:

a) considering the equation:

Minimize $x_{1}^{2} +2x_{2}x^{2} +3x_{3}^{2}+(x_{1} -x_{2} +x_{3} -1)^{2} +(-x_{1} -4x_{2} +2)^{2}$

$A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]$ (matrix A)

vector b

$b=\left[\begin{array}{ccc}0\\1\end{array}\right]$

b) If Pxn is matrix B and p-vector d, we have:

minimize $(-6x_{2}+4)^{2} +(-4x_{1} +3x_{2} -1)+(x_{1} +8x_{2} -3)^{2}$

$Ax=\left[\begin{array}{ccc}0&-6&0\\-4&3&0\\1&8&0\end{array}\right]$

$\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-4\\1\\3\end{array}\right]$

$Ax-b=\left[\begin{array}{ccc}-bx_{2}+4 \\-4x_{1}+3x_{2}-1 \\x_{1}+8x_{2}-3 \end{array}\right] =1$

$||Ax-b||^{2} =(-bx_{2}+4)^{2} (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}$

c) minimize $2(-bx_{2}+4)^{2} +3(-4x_{1} +3x_{2} -1)^{2} +4(x_{1} -x_{2} -3)^{2} -(6\sqrt{2}x_{2} +4\sqrt{2} )^{2} +(-4\sqrt{3} x_{1} +3\sqrt{3}x_{2} -\sqrt{3})^{2} +(2x_{1} -16x_{2} -6)^{2}$

in matrix:

$A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]$

$x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]$

6 0

3 years ago

Factor completely 4ab − 7ax + 8b − 14x.

zloy xaker [14]

The answer i came up with is : (4b-7x) (a+2)

5 0

3 years ago

Read 2 more answers