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Marina CMI [18]
2 years ago
12

Raquel estimated 304,900,000,000 as 3 × 10^8. What error did she make?

Mathematics
1 answer:
kolbaska11 [484]2 years ago
5 0

The error that was made by Raquel when expressing 304,900,000,000

is that she didn't count the digit correctly, The correct digit is 3 *10^{11}

  • Raquel was trying to express the figure in standard form but she doesn't count the number of digit very well and that was her mistake

  • Standard form helps to represent digits that are very long or short in simple form and fir conveniency sake

Therefore, the correct expression in standard form is 3 * 10^{11}

Learn more at: brainly.com/question/9761475?referrer=searchResults

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Sarah bought a $320000 house. She pays 20% down and takes out a 30-year loan for the rest. How much is the loan amount going to
lana [24]
The first thing you do is mutitpy 320,000 by .20 so that you can find the amount of down payment. The down payment would be 64,000. So you subtract 64,000 from 320,000. This leaves a loan amount of 256,000 dollars. The answer is 256,000 dollars .
7 0
3 years ago
What is 170% of 97 tons???
Ede4ka [16]
x=170\% * 97 \\ \\ x= \frac{170}{100} *97 \\ \\ x= \frac{17}{10}*97 \\ \\ x= \frac{1649}{10}=164.9
6 0
3 years ago
Need help use screenshot(SAT Prep) In △ABC, AB = BC = 20 and DE ≈ 9.28. Approximate BD. bd equals?
Lilit [14]

Answer:

5.36

Step-by-step explanation:

Given that:

<BAD = <CAE, therefore, BD = EC

Let's take x to be the length of BD = EC

BD + DE + EC = BC

BC = 20,

BD = EC = x

DE ≈ 9.28

Thus,

x + 9.28 + x = 20

x + x + 9.28 = 20

2x + 9.28 = 20

Subtract 9.28 from both sides

2x + 9.28 - 9.28 = 20 - 9.28

2x = 10.72

Divided both sides by 2 to solve for x

\frac{2x}{2} = \frac{10.72}{2}

x = \frac{10.72}{2}

x = 5.36

BD ≈ 5.36

4 0
3 years ago
Solve the equation and check the solution.
myrzilka [38]

A - 2 1/2 = 1 1/2

Solve for A by adding 2 1/2 to both sides:

A = 1 1/2 + 2 1/2

A = 4

The answer is c. A = 4

Check: 4 - 2 1/2 = 1 1/2

8 0
3 years ago
WILL GIVE BRAINLIEST!!!!
Vesna [10]

(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =

= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}

= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}

= 2^{-16} \times 2^{-12} \times 2^{28} \times 5^{10} \times 5^{-8}

= 2^{-16-12+28} \times 5^{10-8}

= 2^{0} \times 5^{2}

= 1 \times 25

= 25

7 0
3 years ago
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