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Leya [2.2K]
3 years ago
14

Solve the equation below for x. 500 = 25e ^ (2x)

Mathematics
1 answer:
Zigmanuir [339]3 years ago
7 0

Answer:

x = i π n + log(20)/2 for n element Z

Step-by-step explanation:

Solve for x:

500 = 25 e^(2 x)

500 = 25 e^(2 x) is equivalent to 25 e^(2 x) = 500:

25 e^(2 x) = 500

Divide both sides by 25:

e^(2 x) = 20

Take the natural logarithm of both sides:

2 x = 2 i π n + log(20) for n element Z

Divide both sides by 2:

Answer: x = i π n + log(20)/2 for n element Z

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10 - 9 x 5 + 6 x (-2)
olya-2409 [2.1K]

Answer:

The answer to your equation is -47.

Step-by-step explanation:

Follow the order of operations. First do 9*5=45, and 6*-2 to get -12. Next, just finish the equation from left to right to get -47.

5 0
3 years ago
Read 2 more answers
Hello! Any help is appreciated (:
lara [203]

Answer:

yes

Step-by-step explanation:

This relation is a function

Each input value goes to only one output value so the relation is a function

6 0
2 years ago
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2. calculate x <br><br>x+57 <br>52+x <br>85​
Luden [163]

Answer:

try math-way

Step-by-step explanation:

5 0
2 years ago
A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep
prohojiy [21]
The sketch of the parabola is attached below

We have the focus (a,b) = (2, -0.5)
The point P(x,y)
The directrix, c at y=-1.5

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; (2, -0.5) and (x,y).
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
\sqrt{ (x-a)^{2}+ (y-b)^{2} }

Step 2
Find the distance between the point P to the directrix c. It is a vertical distance between y and c, expressed as y-c

Step 3
The equation of parabola is then given as 
\sqrt{ (x-a)^{2}+ (y-b)^{2} }=y-c
(x-a)^{2}+ (y-b)^{2}= (y-c)^{2} ⇒ substituting a, b and c
(x-2)^{2}+ (y--0.5)^{2}  = (y--1.5)^{2}
(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}⇒Rearranging and making y the subject gives

y= \frac{ x^{2} }{2} -2x+1

7 0
3 years ago
An initial population of 415
slamgirl [31]

Answer:

The exponential function to model the duck population is:

f(n)=415*(1.32)^n, where:

x is the duck population

n is the number of years

Step-by-step explanation:

In order to calculate the duck population you can use the formula to calculate future value:

FV=PV*(1+r)^n

FV=future value

PV=present value

r=rate

n=number of periods of time

In this case, the present value is the initial population of 415 and the rate is 32%. You can replace these values on the formula and the exponential function to model the duck population would be:

f(n)=415*(1+0.32)^n

f(n)=415*(1.32)^n, where:

x is the duck population

n is the number of years

3 0
3 years ago
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