X-11 < 36 Answer here
2 answers:
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Answer:
A. see below for a graph
B. f(x, y) = f(0, 15) = 90 is the maximum point
Step-by-step explanation:
A. See below for a graph. The vertices are those defined by the second inequality, since it is completely enclosed by the first inequality: (0, 0), (0, 15), (10, 0)
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B. For f(x, y) = 4x +6y, we have ...
f(0, 0) = 0
f(0, 15) = 6·15 = 90 . . . . . the maximum point
f(10, 0) = 4·10 = 40
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<em>Comment on evaluating the objective function</em>
I find it convenient to draw the line f(x, y) = 0 on the graph and then visually choose the vertex point that will put that line as far as possible from the origin. Here, the objective function is less steep than the feasible region boundary, so vertices toward the top of the graph will maximize the objective function.
Answer:
10
Step-by-step explanation:
so if u draw his paths you get a right triangle and so u can use Pythagoras theorem with is a²+b²=c²
so it will look like
c²= 8²+6²
c²=
c²=10
Answer:
The confidence interval for the mean is given by the following formula:
(1)
And for this case the 95% confidence interval is given by (2.13; 2.37)
We have a point of estimate for the sample mean with this formula:
And for the margin of error we have the following estimation:
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean
population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
(1)
And for this case the 95% confidence interval is given by (2.13; 2.37)
We have a point of estimate for the sample mean with this formula:
And for the margin of error we have the following estimation: