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Mice21 [21]
4 years ago
5

Enter your answer and show all the steps that you use to solve this problem in the space provided. A.Solve a–9=20 B.Solve b–9&gt

;20 C.How is solving the equation in part a similar to solving the inequality in part b? D.How are the solutions different?
Mathematics
1 answer:
Goryan [66]4 years ago
5 0

Answer:

A) The value of a is <u>29</u>.

B) The value of b is <u>greater than 29</u>.

C) In both part A and part B we have used a common property  which is addition property and that we have add 9 on both side of equation in both parts.

D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

Step-by-step explanation:

Solving for Part A.

Given,

a-9=20

We have to solve for a.

a-9=20

By using addition property of equality, we will add both side by 9;

a-9+9=20+9\\a=29

Hence the value of a is <u>29</u>.

Solving for Part B.

Given,

b-9>20

We have to solve for b.

b-9>20

By using addition property of inequality, we will add both side by 9;

b-9+9>20+9\\b>29

Hence the value of b is <u>greater than 29</u>.

Solving for Part C.

In both part A and part B we have used a common property  which is addition property and that we have add 9 on both side of equation in both parts.

Solving for Part D.

The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

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Answer:

2x^2 + 10x + 30 + 95/x-3

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
Moesha is (3g+1) years old and shanti is twice moesha age. find the sum of the ages of moesha and shanti in 2 years time.
SpyIntel [72]

Answer:

1.  In 2 years, sum of the ages of Moesha and Shanti = 9g + 7

2.  When Moesha's age is twice her present age, Shanti's age will be thrice Moesha's present age.

3.  4 years ago, Moesha was 12 years old and Shanti was 28 years old if g = 5.

Step-by-step explanation:

Moesha's age = 3g + 1

It is given that Shanti's age is twice Moesha's age.

So, Shanti's age = 2(3g + 1)

= 6g + 2

In 2 years time,

Moesha's age = (3g + 1) + 2 = 3g + 3

Shanti's age = (6g + 2) + 2 = 6g + 4

Hence, sum of the ages of Moesha and Shanti = (3g + 3) + (6g + 4)

= 9g + 7

Moesha's age will be twice her present age in 3g + 1 years.

After 3g + 1 years, Shanti's age will be (6g + 2) + (3g + 1) = 9g + 3 years.

= 3(3g + 1)

= thrice Moesha's present age

Hence, when Moesha's age is twice her present age, Shanti's age will be thrice Moesha's present age.

If g = 5,

Moesha's present age = 3g + 1

= 3(5) + 1

= 15 + 1

= 16

Shanti's present age = 6g + 2

= 6(5) + 2

= 30 + 2

= 32

Hence, 4 years ago, Moesha was 16-4 = 12 years old and Shanti was 32-4 = 28 years old.


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Answer:

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Step-by-step explanation:

20% = 1/5

3 x 5 = 15

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