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dezoksy [38]
4 years ago
13

Ben is paving a parking lot with the shapes shown.how can he find the area of the parking lot?

Mathematics
1 answer:
ohaa [14]4 years ago
7 0
Ok do 75x150 then 25x40 and then add them together, and ps. do bace x hight
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Anyone know the answer ?!? Let me know please !!!
Andru [333]

Answer:

25/35 = .71 = 71%

Step-by-step explanation:

3 0
3 years ago
What is the surface area of the composite figure shown?
kati45 [8]

Answer:

531 m²

Step-by-step explanation:

9x9x5=405 (5 sides that are 9x9, including the bottom)

1/2x9x7x4=126 (4 triangles on top)

405+126=531

8 0
3 years ago
if anyone is willing to help me with my math homework I have 8 worksheets I need to get finished by tommorow if anyone is willin
Svetradugi [14.3K]
It depends what kind of math it is. Fractions, angles, or something else. I don’t want to give you wrong answers.
5 0
3 years ago
Read 2 more answers
Find all solutions of each equation on the interval 0 ≤ x < 2π.
Korvikt [17]

Answer:

x = 0 or x = \pi.

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}.

This equation will thus become:

\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2.

To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2.

\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2.

Solve this equation for u:

\displaystyle \frac{u^{2} + 1}{u^{2}} = 2.

u^{2} + 1 = 2 u^{2}.

u^{2} = 1.

Given that 0 \le u \le 1, u = 1 is the only possible solution.

\cos^{2}{x} = 1,

x = k \pi, where k\in \mathbb{Z} (i.e., k is an integer.)

Given that 0 \le x < 2\pi,

0 \le k.

k = 0 or k = 1. Accordingly,

x = 0 or x = \pi.

8 0
3 years ago
Read 2 more answers
Averi was trying to factor 4x^2+20x-164x
loris [4]

Answer:

the width is 24

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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