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3 years ago

How does the shape of a cross-section of a 3D figure parallel to the base relate to the volume of the 3D figure?

Mathematics

1 answer:

Ket [755]3 years ago

3 0

Answer:

The shape of each cross-section of a 3D figure, relates to the volume because the area of the cross-section is determined by its shape and the area of this cross section is in the sum that calculates the volume of this 3D figure.

Step-by-step explanation:

An infinite sum of all the all the cross-sections of a 3D figure parallel to the base equals the volume of that 3D figure.

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RSB [31]

The value of p(1), p(-2), and p(8) is 0, 744 and 0 respectively

<h3>What is polynomial function?</h3>

Given the function $p(x)= 192 + 21x^3 + 54x^2 - 3x^4 - 264x$

We are to get the following parameters:

$p(1)= 192 + 21(1)^3 + 54(1)^2 - 3(1)^4 - 264(1)\\p(1)=192+21+54-3-264\\p(1)=0$

For p(-2)

$p(-2)= 192 + 21(-2)^3 + 54(-2)^2 - 3(-2)^4 - 264(-2)\\p(-2)=192-168+216-24+528\\p(-2)=744$

For p(8)

$p(8)=192 + 21(8)^3 + 54(8)^2 - 3(8)^4 - 264(8)\\p(8)=192+10,752+3,456-12,288-2,112\\p(-2)=0$

Hence the value of p(1), p(-2), and p(8) is 0, 744 and 0 respectively

Learn more on polynomials here: brainly.com/question/4142886

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Answer:

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