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Ilia_Sergeevich [38]
3 years ago
13

How does the shape of a cross-section of a 3D figure parallel to the base relate to the volume of the 3D figure?

Mathematics
1 answer:
Ket [755]3 years ago
3 0

Answer:

The shape of each cross-section of a 3D figure,  relates to the volume because the area of the cross-section is determined by its shape and the area of this cross section is in the sum that calculates the volume of this 3D figure.

Step-by-step explanation:

An infinite sum of all the all the cross-sections of a 3D figure parallel to the base equals the volume of that 3D figure.

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F(x) = 4x - 1<br> g(x) = x2 - 4x<br> Find f(g(3))
nasty-shy [4]

Answer:

-13

Step-by-step explanation:

hello,

Replace x by the value as below

g(3)=3^2-4\times3=9-12=-3\\f(g(3))=f(-3)=4\times(-3)-1=-12-1=-13\\

Thanks

5 0
3 years ago
Abena has 1.3kg of apples and plenty of the other ingredients.
Sphinxa [80]

Answer:

No, she can't make for 15 people.

Step-by-step explanation:

For 15 people the mass of apple required is 1.375 kg.

She can only make 14 apple crumbles.

Please mark as brainliest

7 0
3 years ago
Jim spins a spinner with colors red, blue, yellow, purple, green, and orange. Jim also flips a coin. What is the probability tha
S_A_V [24]
Probability=number of specific outcomes/total possible outcomes

And the probability of two events happening at the same time is P(1)*P(2), or the product of the probabilities of each event...

In this case:

P(primary color)=3/6=1/2

P(head)=1/2

P(primary and head)=(1/2)(1/2)=1/4
4 0
3 years ago
Read 2 more answers
Which function grows the fastest for large values of x? f(x)=8x f(x)=3x f(x)=4x2+3 f(x)=1.5x 20 points
Aleonysh [2.5K]
The 4 functions are:
f_1 (x) = 8x
f_2(x)=3x
f_3(x)=4x^2+3
f_4(x)=1.5 x

Let's keep in mind that for large values of x, a quadratic function grows faster than a linear function:
ax^2 \ \textgreater \  kx for large values of x

In this problem, we can see that the only quadratic function is f_3(x), while all the others are linear functions, so the function that grows faster for large values of x is
f_3(x) = 4x^2 +3
7 0
3 years ago
Help!!!!!!!!!!!!!!!!
Andru [333]

Step-by-step explanation:

The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:

let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9

let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9

let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9

let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9

let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9

let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9

You can continue to increase the length of the square and follow this pattern and it will be consistent.

7 0
3 years ago
Read 2 more answers
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