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statuscvo [17]
2 years ago
13

Winston needs at least 80 signatures from students in his school before he can run for class president. He has 23 signatures alr

eady. He and his 2 friends plan to get the remaining signatures during lunch. Which inequality can Winston use to determine the minimum number of signatures each person should get so he can run for class president?
Mathematics
2 answers:
IrinaK [193]2 years ago
6 0

Answer:

Step-by-step explanation:

80> 23+3x

jeyben [28]2 years ago
4 0

Answer:

Step-by-step explanation:

You might be interested in
Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

6 0
3 years ago
A lake has a small patch of lily pads and every day the patch grows to double its size. It takes 32 days for the patch to cover
S_A_V [24]

Answer:

<em>It took 31 days for the patch to cover half the lake</em>

<em></em>

Step-by-step explanation:

The patch grows to double its size everyday

the patch completely covers the lake in 32 days

Since the patch doubles itself everyday, this means that the previous day before the 32nd day, the lake was just half covered.

Therefore, the the patch covered half the lake on the 31st day, i.e <em>it took 31 days for the patch to cover half the lake</em>

<em></em>

6 0
3 years ago
Click each dot on the image to select an answer.
Nezavi [6.7K]
The answer would be b
5 0
1 year ago
I NEED HELPP PLEASEE!!!
Mnenie [13.5K]

Answer:

26.4

31.2

33.3

These are the easy questions, the rest will have a square root and a a number outside.

8 0
3 years ago
Find the length width and height of both then find the whole volume plz help me stuck
Phantasy [73]
3 by 2 by 4
volume =24 (units)

4 by 5 by 5
volume= 100(units)


4 0
2 years ago
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