Answer:
1.
<u>An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.</u>
It emerges from the process of solving the problem as a equation.
2.I begin like:
The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:
for example:
x² − 4=0
x²= 4
doing square root on both side
x = ±2
Thus, the graph will have vertical asymptotes at x = 2 and x = −2.
To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.
Answer:
(2,1)
Step-by-step explanation:

Use trigonometry to find the angle between the segments 3 and 6.
∠XOB = arccos(3/6) = 60°
The measure of arc AB is double that angle, since the figure is symmetrical about the line containing the segment of length 3.
m(arc AB) = 2·60° = 120°
Answer:
Step-by-step explanation:
Alske